Pipe A can fill a tank in 6 hours, pipe B can fill the same tank in 30 hours and pipe C can fill the same tank in 20 hours. The time taken (in hours) by them to fill one-fourth of the same tank if they operate together is:
1
Part filled in one hour by all three together = \(\frac{1}{6} + \frac{1}{30} + \frac{1}{20}\) = \(\frac{10 + 2 + 3}{60}\) = \(\frac{15}{60}\) = \(\frac{1}{4}\).
So together they fill one-fourth of the tank in 1 hour.
Hence, the answer is 1.
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