All Exams Test series for 1 year @ ₹349 only
Question

One cup has juice and water in the ratio 5 ∶ 2, while another cup of the same capacity has them in the ratio 7 ∶ 4, respectively. If contents of both the cups (when full) are poured in a vessel, then what will be the final ratio of water to juice in the vessel?

This question was previously asked in
SSC CGL 2020 Tier-II (English) Previous Year Paper (29-Jan-2022)
The correct answer is

25 ∶ 52

Understanding the Ratio and Mixing Problem

This question involves mixing the contents of two containers, each holding a mixture of juice and water in different ratios. The key is to determine the actual amounts of juice and water contributed by each container when they are combined, and then find the ratio of water to juice in the final mixture.

Calculating Quantities in Each Cup

We are given that both cups have the same capacity. To simplify calculations, let's assume a convenient total capacity for each cup. The ratios are 5 ∶ 2 (total parts 7) and 7 ∶ 4 (total parts 11). A good common capacity would be the Least Common Multiple (LCM) of the total parts, which are 7 and 11.

LCM(7, 11) = 77

Let's assume the capacity of each cup is 77 units.

Cup 1: Juice ∶ Water = 5 ∶ 2

Total parts in Cup 1 = 5 + 2 = 7 parts.

Value of 1 part = $\frac{\text{Total Capacity}}{\text{Total Parts}} = \frac{77}{7} = 11 \text{ units}$.

  • Amount of Juice in Cup 1 = 5 parts $\times$ 11 units/part = $5 \times 11 = 55 \text{ units}$.
  • Amount of Water in Cup 1 = 2 parts $\times$ 11 units/part = $2 \times 11 = 22 \text{ units}$.

Check: Total in Cup 1 = 55 + 22 = 77 units (Matches assumed capacity).

Cup 2: Juice ∶ Water = 7 ∶ 4

Total parts in Cup 2 = 7 + 4 = 11 parts.

Value of 1 part = $\frac{\text{Total Capacity}}{\text{Total Parts}} = \frac{77}{11} = 7 \text{ units}$.

  • Amount of Juice in Cup 2 = 7 parts $\times$ 7 units/part = $7 \times 7 = 49 \text{ units}$.
  • Amount of Water in Cup 2 = 4 parts $\times$ 7 units/part = $4 \times 7 = 28 \text{ units}$.

Check: Total in Cup 2 = 49 + 28 = 77 units (Matches assumed capacity).

Mixing the Contents

Now, the contents of both full cups are poured into a vessel. To find the total amount of juice and water in the vessel, we sum the amounts from each cup.

  • Total amount of Juice in the vessel = Juice from Cup 1 + Juice from Cup 2
  • Total amount of Juice = 55 units + 49 units = 104 units.
  • Total amount of Water in the vessel = Water from Cup 1 + Water from Cup 2
  • Total amount of Water = 22 units + 28 units = 50 units.

Determining the Final Ratio of Water to Juice

The question asks for the final ratio of water to juice. This is the total amount of water divided by the total amount of juice.

Final Ratio (Water ∶ Juice) = Total Water ∶ Total Juice

Final Ratio = 50 ∶ 104

Simplifying the Ratio

The ratio 50 ∶ 104 can be simplified by dividing both numbers by their greatest common divisor. Both 50 and 104 are divisible by 2.

  • $50 \div 2 = 25$
  • $104 \div 2 = 52$

The simplified ratio of water to juice is 25 ∶ 52.

Summary of Calculations

Ratio (Juice ∶ Water) Total Parts Juice (units) Water (units)
Cup 1 5 ∶ 2 7 55 22
Cup 2 7 ∶ 4 11 49 28
Total in Vessel 104 50

Final Ratio (Water ∶ Juice) = 50 ∶ 104 = 25 ∶ 52.

Revision Table: Ratio and Mixing Concepts

Concept Explanation How it Applies Here
Ratio A comparison of two quantities. e.g., a:b means a units of the first quantity for every b units of the second. Used to represent the composition of juice and water in each cup.
Total Parts in a Ratio The sum of the numbers in the ratio (a+b for a:b). Represents the whole quantity relative to the ratio parts. Used to determine the fraction of juice and water in each cup.
Least Common Multiple (LCM) The smallest positive integer that is a multiple of two or more integers. Used to find a convenient common capacity for the cups, simplifying calculations without fractions initially.
Mixing Ratios Combining quantities from different mixtures. Requires calculating the absolute amount of each component from all sources and summing them. We summed the total juice and total water from both cups.
Simplifying Ratios Dividing both parts of a ratio by their greatest common divisor to express it in its simplest form. The final 50:104 ratio was simplified to 25:52.

Additional Information: Working with Ratios

Understanding ratios is fundamental in many mathematical problems. When dealing with mixtures, ratios tell us the proportion of each component. Here are some additional points:

  • Representing Ratios: Ratios can be written as a ∶ b, a/b, or "a to b".
  • Proportions: A proportion is an equation stating that two ratios are equal, e.g., a ∶ b = c ∶ d or a/b = c/d. This is useful when scaling quantities.
  • Total Quantity from Ratio: If a ratio is a ∶ b and the total quantity is T, the amount of the first component is $\frac{a}{a+b} \times T$, and the second is $\frac{b}{a+b} \times T$. We used this idea when distributing the 77 units capacity based on the ratios.
  • Order Matters: The ratio of A to B (A ∶ B) is different from the ratio of B to A (B ∶ A), unless A and B are equal. This is crucial in this problem, as the final answer requires the ratio of *water* to *juice*, not the other way around.
Was this answer helpful?

Similar Questions

  1. In what ratio should cement costing Rs. 250 per bag be mixed with cement costing Rs. 325 per bag so that the cost of the mixture is Rs. 300 per bag. (A bag of cement is 50 kg).

  2. A and B are solutions of acid and water. The ratios of water and acid in A and B are 4 : 5 and 1 : 2 respectively. If x liters of A is mixed with y liters of B, then the ratio of water and acid in the mixture becomes 8 : 13 What is x : y?

  3. How much water (in litres) must be added to 80 litres solution of milk and water containing 10% milk, so that it becomes a 5% milk solution?

  4. If a dairy mixes cow’s milk which contains 10% fat with buffalo’s milk which contains
    20% fat, then the resulting mixture has fat (120/7) % of fat. In what ratio was the
    cow’s milk mixed with buffalo’s milk?

  5. Three bottles of equal capacity have mixture of milk and water in ratio 5 : 7, 7 : 9 and 2 : 1 respectively. These three bottles are emptied into a large bottle. What is the percentage of milk in the new mixture?

  6. A drum contains 80 litres of ethanol. 20 litres of this liquid is removed and replaced with water. 20 litres of this mixture is again removed and replaced with water. How much water (in litres) is present in this drum now?

  7. A jar contains a blend of a fruit juice and water in the ratio 5 ∶ x. When 1 litre of water is added to 4 litres of the blend the ratio of fruit juice to water becomes 1 ∶ 1. What is the value of x?

  8. In what ratio should 20% ethanol solution be mixed with 40% ethanol solution to obtain a 28% ethanol solution?

  9. How many litres of water should be added to a 7.5 litre mixture of acid and water containing acid and water in the ratio of 1 : 2 such that the resultant mixture has 20% acid in it?

  10. A grain trader has 100 bags of rice. He sold some bags at 10% profit and rest at 20% profit. His overall profit on selling these 100 bags was 14%. How many bags did he sell at 20% profit?


Important Questions from To Make a Mixture from Two Mixtures

  1. In a 90 litre solution, acid and water are in the ratio 2 ∶ 1, To make the ratio of acid and water as 1 ∶ 2, how many litre of water should be added to the solution?

  2. How many litres of acid are there in 12 litres of a 20% solution?

  3. The ratio of number of male and female employees in a company was 5 ∶ 4. Some new males and females joined the company in the ratio 2 ∶ 3. The total number of employees become 1620 and the ratio of males to females become 68 ∶ 67. Initially what was the total number of employees in the company?

  4. The ratio of spirit and water in three solutions are 2 : 3, 3 : 4 and 4 : 5 respectively and they are mixed in the ratio 5 : 3 : 2. 318 ml of water is added to 1.26 liters of the solution thus obtained. The ratio of spirit and water in the final solution is

  5. A manufacturer has 600 L of a 12% solution of acid. How many litres of a 30% acid solution must be added to it such that acid content in the resulting mixture will be more than 15% but less than 18%?

Need Expert Advice?
Upcoming Exams
SSC CPO
November 23, 2026
SSC CHSL
November 30, 2026
Test Series
SSC CGL img
SSC
SSC CGL (Tier I + Tier II) 2026 Mock Test Series - Latest Pattern
2509 Tests 6 Tests Free
8804 Attempts
4.2(941)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App