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Question

1 litre of water at 40°C is mixed with 1 litre of water at 60°C. What will be the approximate temperature of water after a certain time?

The correct answer is

Between 40°C and 60°C

Understanding Temperature Mixing

When two quantities of the same substance at different temperatures are mixed, heat energy is transferred from the hotter substance to the colder substance until they reach a thermal equilibrium, meaning they both reach the same final temperature. This process follows the principle of conservation of energy, often described by the principle of calorimetry.

Principle of Calorimetry

The principle of calorimetry states that when heat exchange occurs between two or more bodies in an isolated system, the total heat lost by the hot bodies is equal to the total heat gained by the cold bodies.

In this specific case, we are mixing 1 litre of water at 40°C with 1 litre of water at 60°C. Both are the same substance (water) and have the same volume. Assuming the density and specific heat capacity of water are constant within this temperature range, equal volumes mean equal masses.

Calculating the Final Temperature

Let:

  • \(m_1\) be the mass of the first volume of water (at 40°C)
  • \(T_1\) be the initial temperature of the first volume of water (40°C)
  • \(m_2\) be the mass of the second volume of water (at 60°C)
  • \(T_2\) be the initial temperature of the second volume of water (60°C)
  • \(T_f\) be the final temperature after mixing
  • \(c\) be the specific heat capacity of water

Since the volumes are equal and the substance is the same, we can assume \(m_1 = m_2 = m\).

Heat gained by the colder water = \(m_1 \times c \times (T_f - T_1)\)

Heat lost by the hotter water = \(m_2 \times c \times (T_2 - T_f)\)

According to the principle of calorimetry:

Heat gained = Heat lost

\(m \times c \times (T_f - T_1) = m \times c \times (T_2 - T_f)\)

Since \(m\) and \(c\) are the same and non-zero, we can cancel them:

\(T_f - T_1 = T_2 - T_f\)

\(2T_f = T_1 + T_2\)

\(T_f = \frac{T_1 + T_2}{2}\)

Substituting the given initial temperatures:

\(T_f = \frac{40°\text{C} + 60°\text{C}}{2}\)

\(T_f = \frac{100°\text{C}}{2}\)

\(T_f = 50°\text{C}\)

Conclusion on Final Temperature

The approximate temperature of the water after mixing will be 50°C. This temperature is exactly halfway between the two initial temperatures, 40°C and 60°C.

Therefore, the approximate temperature of water after a certain time will be between 40°C and 60°C.

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Important Questions from To Make a Mixture from Two Mixtures

  1. In a 90 litre solution, acid and water are in the ratio 2 ∶ 1, To make the ratio of acid and water as 1 ∶ 2, how many litre of water should be added to the solution?

  2. In a milk and water solution, the ratio of milk to water is 1 : 4. M litres of milk is added in it and ratio become 1 : 3. Again N litres of water is added in it and ratio become 2 : 7. If N – M = 4, then what is the initial quantity of solution?

  3. A mixture contains acid and alcohol in the ratio of 3 : 2. On adding 10 litres of alcohol in mixture, the ratio of acid to alcohol becomes 3 : 5. The quantity of acid (in litres) in the original mixture was:

  4. How many litres of acid are there in 12 litres of a 20% solution?

  5. Two vessel contain milk and water in the ratio 7 ∶ 8 and 13 ∶ 5. If both vessel are mixed in ratio 1 ∶ 1, find the ratio of milk and water in new mixture?
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