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Match the LIST-I with LIST-II Choose the correct answer from the options given below:

 

The correct answer is
A-III, B-IV, C-I, D-II

To solve this problem, we need to match the type of gas (List-I) with the specific heat capacity ratio \( \frac{C_p}{C_v} \) (List-II). Here's a step-by-step explanation:

1. **Understanding the Specific Heat Capacity Ratio \(\frac{C_p}{C_v}\):**

  • The ratio \(\gamma = \frac{C_p}{C_v}\) is defined as the specific heat ratio of gases.
  • For a monoatomic gas, \(\gamma\) is usually around \(\frac{5}{3}\).
  • For a diatomic non-rigid gas, \(\gamma\) is typically \(\frac{7}{5}\).
  • For a diatomic rigid gas, \(\gamma\) is usually near \(\frac{9}{7}\).
  • For a triatomic rigid gas, \(\gamma\) might be \(\frac{4}{3}\).

2. **Matching the Lists:**

  • **A. Triatomic rigid gas:** \(\frac{C_p}{C_v} = \frac{4}{3}\) (III)
  • **B. Diatomic non-rigid gas:** \(\frac{C_p}{C_v} = \frac{7}{5}\) (IV)
  • **C. Monoatomic gas:** \(\frac{C_p}{C_v} = \frac{5}{3}\) (I)
  • **D. Diatomic rigid gas:** \(\frac{C_p}{C_v} = \frac{9}{7}\) (II)

Therefore, the correct match is:

  1. A-III: Triatomic rigid gas is matched with \(\frac{C_p}{C_v} = \frac{4}{3}\).
  2. B-IV: Diatomic non-rigid gas is matched with \(\frac{C_p}{C_v} = \frac{7}{5}\).
  3. C-I: Monoatomic gas is matched with \(\frac{C_p}{C_v} = \frac{5}{3}\).
  4. D-II: Diatomic rigid gas is matched with \(\frac{C_p}{C_v} = \frac{9}{7}\).

Thus, the correct answer is A-III, B-IV, C-I, D-II.

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Similar Questions

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Important Questions from Heat and Thermodynamics

  1. During the melting of a slab of ice at $273 \ K$ at atmospheric pressure:

  2. $\gamma_A$ is the specific heat ratio of monoatomic gas A having 3 translational degrees of freedom. $\gamma_B$ is the specific heat ratio of polyatomic gas B having 3 translational, 3 rotational degrees of freedom and 1 vibrational mode. If $\frac{\gamma_A}{\gamma_B} = \left(1 + \frac{1}{n}\right)$, then the value of n is _________.
  3. Match List - I with List - II.
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    (B) Isochoric(II) $\Delta Q = \Delta U$
    (C) Adiabatic(III) $\Delta Q = \text{zero}$
    (D) Isothermal(IV) $\Delta Q = \Delta U + P\Delta V$
    $\Delta Q$=Heat supplied
    $\Delta W$ = Work done by the system
    $\Delta U$=Change in internal energy
    P = Pressure of the system
    $\Delta V$ = Change in volume of the system
    Choose the correct answer from the options given below :
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  5. An ideal gas has undergone through the cyclic process as shown in the figure. Work done by the gas in the entire cycle is ________ $\times 10^{-1}$J.

    (Take $\pi = 3.14$)

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