A monoatomic gas having $\gamma = \frac{5}{3}$ is stored in a thermally insulated container and the gas is suddenly compressed to $\frac{1}{8}^{\text{th}}$ of its initial volume. The ratio of final pressure and initial pressure is: ($\gamma$ is the ratio of specific heats of the gas at constant pressure and at constant volume)
The problem involves a monoatomic gas undergoing a sudden compression in a thermally insulated container. This scenario represents an adiabatic process, where no heat is exchanged between the system and the surroundings. The relationship between pressure ($P$) and volume ($V$) for an adiabatic process is given by:
$P V^\gamma = \text{constant}$
Where $\gamma$ is the adiabatic index (ratio of specific heats).
For the initial state (1) and the final state (2), we can write:
$P_1 V_1^\gamma = P_2 V_2^\gamma$
We need to find the ratio of the final pressure ($P_2$) to the initial pressure ($P_1$). Rearranging the formula:
$\frac{P_2}{P_1} = \left(\frac{V_1}{V_2}\right)^\gamma$
Substitute the values of $\frac{V_1}{V_2}$ and $\gamma$ into the pressure ratio equation:
$\frac{P_2}{P_1} = (8)^{\frac{5}{3}}$
Express 8 as a power of 2 ($8 = 2^3$):
$\frac{P_2}{P_1} = (2^3)^{\frac{5}{3}}$
Using the power rule $(a^m)^n = a^{m \times n}$:
$\frac{P_2}{P_1} = 2^{3 \times \frac{5}{3}} = 2^5$
Calculate $2^5$:
$2^5 = 32$
Therefore, the ratio of the final pressure and initial pressure ($\frac{P_2}{P_1}$) is 32.
During the melting of a slab of ice at $273 \ K$ at atmospheric pressure:
| List - I | List - II |
| (A) Isobaric | (I) $\Delta Q = \Delta W$ |
| (B) Isochoric | (II) $\Delta Q = \Delta U$ |
| (C) Adiabatic | (III) $\Delta Q = \text{zero}$ |
| (D) Isothermal | (IV) $\Delta Q = \Delta U + P\Delta V$ |
Match the LIST-I with LIST-II Choose the correct answer from the options given below:

An ideal gas has undergone through the cyclic process as shown in the figure. Work done by the gas in the entire cycle is ________ $\times 10^{-1}$J.
(Take $\pi = 3.14$)

Water falls from a height of $200 \text{ m}$ into a pool. Calculate the rise in temperature of the water assuming no heat dissipation from the water in the pool.
(Take $g = 10 \text{ m/s}^2$, specific heat of water $= 4200 \text{ J/(kg K)}$)
During the melting of a slab of ice at $273 \ K$ at atmospheric pressure:
| List - I | List - II |
| (A) Isobaric | (I) $\Delta Q = \Delta W$ |
| (B) Isochoric | (II) $\Delta Q = \Delta U$ |
| (C) Adiabatic | (III) $\Delta Q = \text{zero}$ |
| (D) Isothermal | (IV) $\Delta Q = \Delta U + P\Delta V$ |
Match the LIST-I with LIST-II Choose the correct answer from the options given below:
