I. Q can be a perfect square.
II. Q is positive for all real values of x.
Select the answer using the code given below :
To solve the given problem, we need to analyze the equation \( Q = x^2 + bx + c \) under the condition that the sum of the roots is equal to the product of the roots.
We know that for a quadratic equation \( ax^2 + bx + c = 0 \) (in this case, \( a = 1 \) for \( x^2 + bx + c = 0 \)), the sum of the roots \( \alpha + \beta \) is given by \( -\frac{b}{a} \), and the product of the roots \( \alpha \beta \) is \(\frac{c}{a}\).
Given:
The sum of the roots = Product of the roots.
\(-\frac{b}{1} = \frac{c}{1}\)
This simplifies to:
\(b = -c\)
Now, let's analyze each statement:
Therefore, the correct choice is I only.
Consider the following in respect of a positive real number \(x\) :
I. \(x+\frac{1}{x} >1\)
II. \(x+\frac{1}{x} > 2\)
III. \((x+\frac{1}{x})^2 > 9\)
Which of the above are correct?
Let $p, q$ be the roots of the equation $x^2 + mx - n = 0$ and $m, n$ be the roots of the equation $x^2 + px - q = 0$ ($m, n, p, q$ are non-zero numbers). Which of the following statements is/are correct?
I. $m(m + n) = -1$
II. $p + q = 1$
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If the roots of the equation \(x^2-(k-2)x + (k + 1) = 0\) are equal, then what are the values of \(k\)?
Find the minimum value of 2x² – 5x – 3 and also find x.
A quadratic equation $x^2 + 3x + k = 0$ has a discriminant equal to 9. What is the value of k?
If both roots of the quadratic equation, $x^2 + 3x + 2 = 0$, are also roots of another quadratic equation, $ax^2 + bx + c = 0$, then which of the following must be true?