Let d(n) denote the number of positive divisors of a positive integer n. Which of the following are correct? 1. d(5) = d(11) Select the correct answer using the code given below:
2. d(5).d(11) = d(55)
3. d(5) + d(11) = d(16)
1 and 2 only
The function d(n) represents the number of positive divisors of a positive integer n. A divisor is a number that divides n evenly without leaving a remainder. To find d(n) for a small number, we can list all its positive divisors and count them.
Let's calculate the number of positive divisors for each integer mentioned in the statements: 5, 11, 55, and 16.
Now that we have calculated the number of positive divisors for each integer, let's evaluate the correctness of the given statements.
We will check each statement using the values we calculated:
Based on our analysis, Statement 1 (\(d(5) = d(11)\)) and Statement 2 (\(d(5) \cdot d(11) = d(55)\)) are correct, while Statement 3 (\(d(5) + d(11) = d(16)\)) is incorrect.
Therefore, the correct answer is the one indicating that only statements 1 and 2 are correct.
| Integer (n) | Positive Divisors of n | Number of Divisors (d(n)) | Statement Checked | Evaluation | Correct? |
|---|---|---|---|---|---|
| 5 | 1, 5 | d(5) = 2 | Statement 1: \(d(5) = d(11)\) | \(2 = 2\) | Correct |
| 11 | 1, 11 | d(11) = 2 | |||
| 55 | 1, 5, 11, 55 | d(55) = 4 | Statement 2: \(d(5) \cdot d(11) = d(55)\) | \(2 \cdot 2 = 4\) | Correct |
| 16 | 1, 2, 4, 8, 16 | d(16) = 5 | Statement 3: \(d(5) + d(11) = d(16)\) | \(2 + 2 = 5\) | Incorrect |
The divisor function d(n), also often denoted as \(\tau(n)\) or \(\sigma_0(n)\), is an important function in number theory. It counts the number of positive divisors of a positive integer n.
A more general way to calculate d(n) for any positive integer n is using its prime factorization. If the prime factorization of n is given by \(n = p_1^{a_1} p_2^{a_2} \cdots p_k^{a_k}\), where \(p_1, p_2, \ldots, p_k\) are distinct prime numbers and \(a_1, a_2, \ldots, a_k\) are positive integers, then the number of positive divisors of n is given by the formula:
\[d(n) = (a_1 + 1)(a_2 + 1)\cdots(a_k + 1)\]
Let's apply this formula to the numbers in the question:
These results match the results we got by listing divisors, confirming the formula's correctness.
The property observed in Statement 2, \(d(mn) = d(m)d(n)\) when \(\gcd(m, n) = 1\), means that the divisor function d(n) is a multiplicative function. This is a significant property in number theory and holds when m and n are coprime (have no common positive divisors other than 1).
Consider the following statements in respect of all factors of 360 :
1. The number of factors is 24.
2. The sum of all factors is 1170.
Which of the above statements is/are correct ?
If n is any natural number, then 5 2n - 1 is always divisible by a minimum of how many natural numbers?
Pick out the set that forms the factors of 36.
The sum of all the factors of 100 is
How many zeroes are there at the end of the following product?
1 × 5 × 10 × 15 × 20 × 30 × 35 × 40 × 45 × 50 × 55 × 60
The number of unique prime divisor of 960 is:
Find the total number of zeroes at the end of the product of $2000! \times 1200!$