Consider the following statements in respect of all factors of 360 : 1. The number of factors is 24. 2. The sum of all factors is 1170. Which of the above statements is/are correct ?
Both 1 and 2
The question asks us to consider two statements about the factors of the number 360. We need to determine if these statements are correct. To do this, we first need to understand how to find the factors of a number, specifically the number of factors and the sum of its factors.
To find the factors of any number, it's best to start by finding its prime factorization. Prime factorization is breaking down a number into the product of its prime numbers.
Let's find the prime factors of 360:
So, \(360 = (2 \times 5) \times (2 \times 3) \times (2 \times 3)\)
Combining the prime factors:
\(360 = 2 \times 2 \times 2 \times 3 \times 3 \times 5\)
In exponential form, the prime factorization is:
\(360 = 2^3 \times 3^2 \times 5^1\)
Statement 1 says: The number of factors is 24.
To find the number of factors of a number given its prime factorization \(N = p_1^{a_1} p_2^{a_2} \dots p_k^{a_k}\), the formula is \((a_1+1)(a_2+1)\dots(a_k+1)\).
For 360, the prime factorization is \(2^3 \times 3^2 \times 5^1\). Here, the exponents are \(a_1=3\), \(a_2=2\), and \(a_3=1\).
Using the formula, the number of factors is:
\((3+1)(2+1)(1+1) = 4 \times 3 \times 2\)
Calculation:
\(4 \times 3 = 12\)
\(12 \times 2 = 24\)
So, the number of factors of 360 is 24. Statement 1 is correct.
| Prime Factor | Exponent (\(a_i\)) | (\(a_i+1\)) |
|---|---|---|
| 2 | 3 | \(3+1=4\) |
| 3 | 2 | \(2+1=3\) |
| 5 | 1 | \(1+1=2\) |
Total number of factors = Product of (\(a_i+1\)) values = \(4 \times 3 \times 2 = 24\).
Statement 2 says: The sum of all factors is 1170.
To find the sum of factors of a number given its prime factorization \(N = p_1^{a_1} p_2^{a_2} \dots p_k^{a_k}\), the formula is \((1+p_1+\dots+p_1^{a_1})(1+p_2+\dots+p_2^{a_2})\dots(1+p_k+\dots+p_k^{a_k})\).
For 360, with prime factorization \(2^3 \times 3^2 \times 5^1\), the sum of factors is:
\((1+2^1+2^2+2^3)(1+3^1+3^2)(1+5^1)\)
Let's calculate each part:
The sum of all factors is the product of these sums:
\(15 \times 13 \times 6\)
Calculation:
\(15 \times 13 = 195\)
\(195 \times 6 = 1170\)
So, the sum of all factors of 360 is 1170. Statement 2 is correct.
| Prime Factor \(p_i\) | Exponent \(a_i\) | Sum of powers \((1+p_i+\dots+p_i^{a_i})\) |
|---|---|---|
| 2 | 3 | \(1+2+2^2+2^3 = 1+2+4+8 = 15\) |
| 3 | 2 | \(1+3+3^2 = 1+3+9 = 13\) |
| 5 | 1 | \(1+5 = 6\) |
Sum of factors = \(15 \times 13 \times 6 = 1170\).
Based on our calculations, both Statement 1 (The number of factors is 24) and Statement 2 (The sum of all factors is 1170) are correct for the number 360.
| Property | Calculation Method | Result for 360 | Statement Status |
|---|---|---|---|
| Prime Factorization | Break down into prime numbers | \(2^3 \times 3^2 \times 5^1\) | N/A |
| Number of Factors | \((a_1+1)(a_2+1)\dots\) | \((3+1)(2+1)(1+1) = 24\) | Statement 1 Correct |
| Sum of Factors | \((1+p_1+\dots)(1+p_2+\dots)\dots\) | \((1+2+4+8)(1+3+9)(1+5) = 15 \times 13 \times 6 = 1170\) | Statement 2 Correct |
Understanding factors, prime factorization, number of factors, and sum of factors are key concepts in number theory. These methods can be applied to any positive integer to determine its divisors and related properties.
Pick out the set that forms the factors of 36.
If n is any natural number, then 5 2n - 1 is always divisible by a minimum of how many natural numbers?
Let d(n) denote the number of positive divisors of a positive integer n. Which of the following are correct?
1. d(5) = d(11)
2. d(5).d(11) = d(55)
3. d(5) + d(11) = d(16)
Select the correct answer using the code given below:
The sum of all the factors of 100 is
How many zeroes are there at the end of the following product?
1 × 5 × 10 × 15 × 20 × 30 × 35 × 40 × 45 × 50 × 55 × 60