Let A(3, -1) and B(1, 1) be the end points of line segment AB. Let P be the middle point of the line segment AB. Let Q be the point situated at a distance √2 units from P on the perpendicular bisector line of AB. What are the possible coordinates of Q?
(2, 1)
After calculating the distance and finding the perpendicular bisector, we find that the coordinates of Q are (2, 1).
If p and q are real numbers between 0 and 1 such that the points (p, 1), (1, q), and (0, 0) form an equilateral triangle, then what is (p + q) equal to?
The vertices of a triangle are A(1, 1), B(0, 0), and C(2, 0). The angular bisectors of the triangle meet at P. What are the coordinates of P?
The graphs of the linear equations 4x - 2y = 10 and 4x + ky = 2 intersect at a point (a, 4). The value of k is equal to:
In which ratio the point (-3, p) divides the line segment joining the points (-5, -4) and (-2, 3)?
The area (in sq. units) of the triangle formed by the graphs of 8x + 3y = 24, 2x + 8 = y and the x-axis is:
In which quadrant both abscissa and ordinate are negative?
Find the slope of the line joining the points (3, -4) and (5, 2).