PQR is a triangle such that QP = QR = 15 cm and PR = 18 cm. PN, QM and RT are the altitudes of the triangle which intersect at O.
What is \(QT : QO\) equal to?
4 : 5
Place \(P=(-9,0)\), \(R=(9,0)\); since \(QP=QR=15\), \(Q=(0,12)\) (as \(9^2+12^2=15^2\)). The altitude QM is the y-axis, so \(M=(0,0)\). The foot of the altitude from R onto QP works out to \(T=(-63/25,\,216/25)\), and solving for the intersection of the altitudes gives the orthocentre \(O=(0,27/4)\). Then \(QT=\frac{21}{5}\) and \(QO=12-\frac{27}{4}=\frac{21}{4}\), so \(QT:QO=\frac{21}{5}:\frac{21}{4}=4:5\).
Each side of a square subtends an angle of 60° at the tip of a tower of height h meters standing at the centre of the square. If l is the length of each side of the square, then what is h 2equal to?
If x is the perimeter, in cm, of the triangle, then which one of the following is correct?
If y is the area in cm² of the triangle, then which one of the following is correct?
What is the ratio of \(AB^2 : BP^2 : PR^2\)?
What is the ratio of the area of Δ PRB to the area of Δ PQC?
What is the ratio of QO to OM?
A Question is given followed by two Statements I and II. Consider the Question and the Statements and mark the correct option.
Question: ABC is a triangle right-angled at A and AD is perpendicular to BC. If AD = \(7.2\) cm, then what is \(BD \times CD\) equal to?
Statement I: \(AB : AC = 3 : 4\).
Statement II: \(BC = 15\) cm.
Which one of the following is correct in respect of the above Question and Statements?
A square of maximum area is inscribed in an equilateral triangle. If the side of the triangle is equal to \((6+4\sqrt{3})\) cm, then what is the area of the square?
If \(A + B + C = \pi\) \((A, B, C > 0)\) and the angle C is obtuse, then which of the following is/are correct?
I. \(\sin A . \sin B < 1\)
II. \(\tan A . \tan B > 1\)
Select the answer using the code given below:
ABC is a triangle such that \(\angle ABC = 120^\circ\). If BD is the bisector of \(\angle B\) that meets AC at D, then what is the ratio of the area of \(\triangle ABD\) to the area of \(\triangle CBD\)?
In a triangle ABC, a = (1 + √3) cm, b = 2 cm and angle C = 60°, then the other two angles are
Which of the following measures can form a triangle?
If in a triangle ABC, \(\frac{{2\cos A}}{a} + \frac{{\cos B}}{b} + \frac{{2\cos C}}{c} = \frac{a}{{bc}} + \frac{b}{{ca}}\) then the value of the angle A is
In a triangle ABC, sec A (sin B cos C + cos B sin C) equals:
Consider the following statements :
1. ABC is right angled triangle
2. The angles of the triangle are in AP
Which of the statements given above is/are correct ?