The fringe width ($\beta$) in Young's double-slit experiment is determined by the wavelength of light ($\lambda$), the distance between the slits and the screen ($D$), and the separation between the slits ($d$). The formula is:
$ \beta = \frac{\lambda D}{d} $
The problem states that two separate experimental set-ups produce fringes of equal width. Let the parameters for the two set-ups be subscripted with 1 and 2.
Therefore, we have:
$ \beta_1 = \beta_2 $
Substituting the formula for fringe width:
$ \frac{\lambda_1 D_1}{d_1} = \frac{\lambda_2 D_2}{d_2} $
We need to find the ratio of the distances between the slits and the screens, which is $D_1/D_2$. Rearranging the equation from the previous step:
$ \frac{D_1}{D_2} = \frac{\lambda_2}{\lambda_1} \times \frac{d_1}{d_2} $
The problem provides the following ratios:
Substitute these values into the rearranged equation:
$ \frac{D_1}{D_2} = \left(\frac{2}{1}\right) \times \left(\frac{2}{1}\right) $
$ \frac{D_1}{D_2} = \frac{4}{1} $
The corresponding ratio of the distances ($D_1/D_2$) is 4.
A ring is placed at the bottom of a trough containing four immiscible liquids of refractive indices $1.0, 2.0, 3.0$ and $4.0$ poured one above the other of heights $10$ cm, $20$ cm, $30$ cm, and $40$ cm respectively. The apparent depth at which the ring appears, when seen from outside is____________ cm.
A plane polarized light is incident on a polariser with its pass axis making angle $\theta$ with x-axis, as shown in the figure. At four different values of $\theta$, $\theta = 8^\circ, 38^\circ, 188^\circ$ and $218^\circ$, the observed intensities are same. What is the angle between the direction of polarization and x-axis ?
