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In two separate Young's double-slit experimental set-ups and two monochromatic light sources of different wavelengths are used to get fringes of equal width. The ratios of the slits separations and that of the wavelengths of light used are $2 : 1$ and $1 : 2$ respectively. The corresponding ratio of the distances between the slits and the respective screens ($D_1/D_2$) is ___________.

Young's Double-Slit: Fringe Width Calculation

The fringe width ($\beta$) in Young's double-slit experiment is determined by the wavelength of light ($\lambda$), the distance between the slits and the screen ($D$), and the separation between the slits ($d$). The formula is:

$ \beta = \frac{\lambda D}{d} $

Equal Fringe Width Condition

The problem states that two separate experimental set-ups produce fringes of equal width. Let the parameters for the two set-ups be subscripted with 1 and 2.

Therefore, we have:

$ \beta_1 = \beta_2 $

Substituting the formula for fringe width:

$ \frac{\lambda_1 D_1}{d_1} = \frac{\lambda_2 D_2}{d_2} $

Calculating the Distance Ratio

We need to find the ratio of the distances between the slits and the screens, which is $D_1/D_2$. Rearranging the equation from the previous step:

$ \frac{D_1}{D_2} = \frac{\lambda_2}{\lambda_1} \times \frac{d_1}{d_2} $

Applying Given Ratios

The problem provides the following ratios:

  • Ratio of slit separations: $d_1 : d_2 = 2 : 1 \implies \frac{d_1}{d_2} = \frac{2}{1}$
  • Ratio of wavelengths: $\lambda_1 : \lambda_2 = 1 : 2 \implies \frac{\lambda_1}{\lambda_2} = \frac{1}{2}$. This implies $\frac{\lambda_2}{\lambda_1} = \frac{2}{1}$.

Substitute these values into the rearranged equation:

$ \frac{D_1}{D_2} = \left(\frac{2}{1}\right) \times \left(\frac{2}{1}\right) $

$ \frac{D_1}{D_2} = \frac{4}{1} $

The corresponding ratio of the distances ($D_1/D_2$) is 4.

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