The problem involves calculating the refractive index of a transparent sheet placed in a Young's double-slit experiment, given the fringe shift.
When a thin transparent sheet of thickness $t$ and refractive index $\mu$ is introduced in front of one slit, the central bright fringe shifts. The formula for this shift $\Delta y$ is:
$ \Delta y = \frac{D}{d}(\mu - 1)t $The refractive index is given as $\mu = \frac{\alpha}{10}$. Equating this with the calculated value:
$ 1.4 = \frac{\alpha}{10} $Solve for $\alpha$:
$ \alpha = 1.4 \times 10 = 14 $Therefore, the value of $\alpha$ is 14.
A ring is placed at the bottom of a trough containing four immiscible liquids of refractive indices $1.0, 2.0, 3.0$ and $4.0$ poured one above the other of heights $10$ cm, $20$ cm, $30$ cm, and $40$ cm respectively. The apparent depth at which the ring appears, when seen from outside is____________ cm.
A plane polarized light is incident on a polariser with its pass axis making angle $\theta$ with x-axis, as shown in the figure. At four different values of $\theta$, $\theta = 8^\circ, 38^\circ, 188^\circ$ and $218^\circ$, the observed intensities are same. What is the angle between the direction of polarization and x-axis ?
