The given series is $8, 19, 30, \dots$. To understand the pattern, let's find the difference between consecutive terms:
Since the difference between consecutive terms is constant (11), this is an arithmetic progression (AP). In an AP, each term after the first is obtained by adding a fixed, non-zero number called the common difference.
We need to find the 10th term of this series. We can use the formula for the $n$-th term of an arithmetic progression:
$$a_n = a_1 + (n-1)d$$
Where:
From the given series $8, 19, 30, \dots$:
$$a_{10} = 8 + (10-1) \times 11$$
$$a_{10} = 8 + (9) \times 11$$
$$a_{10} = 8 + 99$$
$$a_{10} = 107$$
Therefore, the 10th term of the arithmetic series $8, 19, 30, \dots$ is 107.
If the arithmetic mean of a, b, c is \(\rm \frac M 3\) and \(\rm \frac{1}{a} + \frac{1}{b} = -\frac{1}{c} \) , then the arithmetic mean of a 2, b 2, c 2 is
How many two-digit numbers are divisible by 3 ?
A person saves Rs. 1000 more than he did the previous year. If he saves Rs. 2000 in the first year, in how many years will he save Rs. 170000?
A car starts with a speed of 60 km/h with its speed increasing every one hour by 5 km/h. In how many hours will it cover 435 kms?
How many natural numbers lie between 3 and 200 which are divisible by 7?