In the following question, select the missing number from the given series. 2, 3, 10, 39, ?, 1175
196
The question asks us to identify the missing number in the given series: 2, 3, 10, 39, ?, 1175.
To solve this, we need to analyze the relationship between consecutive terms in the number series to find a pattern.
Let's look at the relationship between each term and its preceding term:
Observing these calculations, we can see a pattern emerging. The pattern involves multiplying the previous term by a number that increases sequentially (2, 3, 4, ...) and then either adding 1 or subtracting 1, with the operation alternating (-1, +1, -1).
The pattern seems to be: Term$_n$ = Term$_{n-1}$ \(\times\) n + \((\text{-}1)^{n-1}\)
Let's verify this rule with the given terms:
The missing number is the 5th term in the series (n=5). Using the pattern:
Term$_5$ = Term$_4$ \(\times\) 5 + \((\text{-1})^{5-1}\)
Term$_5$ = \(39 \times 5 + (\text{-1})^4\)
Term$_5$ = \(195 + 1\)
Term$_5$ = \(196\)
Let's verify if the 6th term (1175) follows the pattern using our calculated 5th term (196):
Term$_6$ = Term$_5$ \(\times\) 6 + \((\text{-1})^{6-1}\)
Term$_6$ = \(196 \times 6 + (\text{-1})^5\)
Term$_6$ = \(1176 - 1\)
Term$_6$ = \(1175\)
This matches the last term in the given series, confirming our pattern and the calculated missing number are correct.
Based on the identified pattern, the missing number in the series 2, 3, 10, 39, ?, 1175 is 196.
The correct option is 196.
| Step (n) | Term$_{n-1}$ | Operation | Term$_n$ Calculation | Term$_n$ |
|---|---|---|---|---|
| 2 | 2 | \(\times\) 2 - 1 | \(2 \times 2 - 1\) | 3 |
| 3 | 3 | \(\times\) 3 + 1 | \(3 \times 3 + 1\) | 10 |
| 4 | 10 | \(\times\) 4 - 1 | \(10 \times 4 - 1\) | 39 |
| 5 (Missing) | 39 | \(\times\) 5 + 1 | \(39 \times 5 + 1\) | 196 |
| 6 | 196 | \(\times\) 6 - 1 | \(196 \times 6 - 1\) | 1175 |
Number series questions are common in logical reasoning and quantitative aptitude tests. To solve them, you should look for patterns based on:
Systematically checking for these common patterns will help you solve most number series questions.
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