In the examination, Raushan got 25% marks and failed by 64 marks. If he had got 40% marks he would have secured 32 marks more than the pass marks. Find the percentage of pass marks in the examination.
35%
This question requires us to determine the percentage of pass marks in an examination. We are given information about a student, Raushan, and his performance in two different hypothetical scenarios.
Our goal is to find the pass marks as a percentage of the total marks.
Let's define the variables:
Now, we translate the given information into mathematical equations:
From Scenario 1:
From Scenario 2:
We now have two equations representing the pass marks (P). By setting them equal to each other, we can solve for the total marks (M):
$0.25 \times M + 64 = 0.40 \times M - 32$
Let's rearrange the equation to solve for M:
$64 + 32 = 0.40 \times M - 0.25 \times M$
$96 = 0.15 \times M$
To find M, we divide 96 by 0.15:
$M = \frac{96}{0.15}$
$M = \frac{9600}{15}$
$M = 640$
So, the total marks in the examination are 640.
Now that we know the total marks (M = 640), we can calculate the pass marks (P) using either Equation 1 or Equation 2.
Using Equation 1:
$P = 0.25 \times M + 64$
$P = 0.25 \times 640 + 64$
$P = 160 + 64$
$P = 224$
Using Equation 2 for verification:
$P = 0.40 \times M - 32$
$P = 0.40 \times 640 - 32$
$P = 256 - 32$
$P = 224$
The pass marks required for the examination are 224.
The final step is to calculate the percentage of pass marks. This is done by dividing the pass marks (P) by the total marks (M) and multiplying the result by 100.
Pass Marks Percentage $= \frac{P}{M} \times 100$
Substitute the values P = 224 and M = 640:
Pass Marks Percentage $= \frac{224}{640} \times 100$
Simplify the fraction $\frac{224}{640}$:
$\frac{224}{640} = \frac{7 \times 32}{20 \times 32} = \frac{7}{20}$
Now, convert the fraction to a percentage:
Pass Marks Percentage $= \frac{7}{20} \times 100$
Pass Marks Percentage $= 7 \times 5$
Pass Marks Percentage $= 35\%$
The percentage of pass marks in the examination is 35%.
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