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Question

In the context of tiling a plane surface, which of the following polygons is the odd one out?

The correct answer is
Regular pentagon

Tiling Plane Surfaces with Regular Polygons

To determine which regular polygon is the odd one out in tiling a plane surface, we need to check if the polygon can tessellate. A tessellation (or tiling) covers a plane with shapes having no overlaps or gaps. For a regular polygon to tessellate, the sum of the interior angles meeting at any vertex must equal exactly 360 degrees.

Calculating Interior Angles

The formula for the interior angle of a regular n-sided polygon is:

$ \text{Interior Angle} = \frac{(n-2) \times 180^\circ}{n} $

Analyzing Each Polygon

  • Equilateral Triangle (n=3):
    • Interior Angle = $ \frac{(3-2) \times 180^\circ}{3} = \frac{180^\circ}{3} = 60^\circ $
    • Number of triangles meeting at a vertex = $ \frac{360^\circ}{60^\circ} = 6 $.
    • Since 6 triangles fit perfectly ($6 \times 60^\circ = 360^\circ$), equilateral triangles can tile a plane.
  • Square (n=4):
    • Interior Angle = $ \frac{(4-2) \times 180^\circ}{4} = \frac{360^\circ}{4} = 90^\circ $
    • Number of squares meeting at a vertex = $ \frac{360^\circ}{90^\circ} = 4 $.
    • Since 4 squares fit perfectly ($4 \times 90^\circ = 360^\circ$), squares can tile a plane.
  • Regular Pentagon (n=5):
    • Interior Angle = $ \frac{(5-2) \times 180^\circ}{5} = \frac{540^\circ}{5} = 108^\circ $
    • Number of pentagons meeting at a vertex = $ \frac{360^\circ}{108^\circ} \approx 3.33 $.
    • Since $360^\circ$ is not perfectly divisible by $108^\circ$, a whole number of pentagons cannot meet at a vertex without gaps or overlaps. Regular pentagons cannot tile a plane by themselves.
  • Regular Hexagon (n=6):
    • Interior Angle = $ \frac{(6-2) \times 180^\circ}{6} = \frac{720^\circ}{6} = 120^\circ $
    • Number of hexagons meeting at a vertex = $ \frac{360^\circ}{120^\circ} = 3 $.
    • Since 3 hexagons fit perfectly ($3 \times 120^\circ = 360^\circ$), regular hexagons can tile a plane.

Conclusion on Tiling

The regular polygons that can tile a plane are the equilateral triangle, the square, and the regular hexagon. The regular pentagon is the odd one out because its interior angles do not allow for a combination that sums to exactly 360 degrees at any vertex, preventing it from forming a tessellation.

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Important Questions from Geometry (Notes)

  1. A 6 cm long chord of a circle is at a distance of 4 cm from the centre of the circle. Find the distance of 8 cm long chord of the same circle from the centre.
  2. In a triangle PQR, if $\angle P + \angle R = 150^\circ$ and $\angle P + 3\angle Q = 170^\circ$, then $\angle P$ is equal to :
  3. PQR is a triangle. The bisectors of the internal angle $\angle Q$ and external angle $\angle R$ intersect at M. If $\angle QMR = 40^\circ$, then $\angle P$ is :
  4. A $2\text{ m}$ long ladder is to reach a wall of height $1.75\text{ m}$. The largest possible horizontal distance of the ladder from the wall could be
  5. Three-quarters of a circle is shown in the figure; OA and OB are two radii perpendicular to each other. C is a point on the circle.

    What is angle ACB?

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