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Question

A $2\text{ m}$ long ladder is to reach a wall of height $1.75\text{ m}$. The largest possible horizontal distance of the ladder from the wall could be

The correct answer is
slightly less than $1\text{ m}$

Ladder Problem: Applying Pythagorean Theorem

This problem involves a right-angled triangle formed by the ladder, the wall, and the ground. We can use the Pythagorean theorem to find the unknown horizontal distance.

  • Let the length of the ladder be the hypotenuse, $L = 2\text{ m}$.
  • Let the height of the wall be one leg, $H = 1.75\text{ m}$.
  • Let the horizontal distance from the wall be the other leg, $D$.

Calculating Horizontal Distance

According to the Pythagorean theorem: $D^2 + H^2 = L^2$

We need to find $D$. Rearranging the formula:

$D^2 = L^2 - H^2$

Substitute the given values:

$D^2 = (2)^2 - (1.75)^2$

$D^2 = 4 - 3.0625$

$D^2 = 0.9375$

Now, take the square root to find $D$:

$D = \sqrt{0.9375}$

Determining the Correct Option

We need to estimate the value of $\sqrt{0.9375}$.

  • We know that $\sqrt{1} = 1$.
  • Since $0.9375$ is less than $1$, its square root must also be less than $1$.
  • Calculating the value gives $D \approx 0.9682\text{ m}$.

Therefore, the largest possible horizontal distance $D$ is approximately $0.9682\text{ m}$, which is slightly less than $1\text{ m}$.

The correct option is the one describing a distance slightly less than $1\text{ m}$.

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Important Questions from Geometry (Notes)

  1. Which of the following is not true for a parallelogram?
  2. A 6 cm long chord of a circle is at a distance of 4 cm from the centre of the circle. Find the distance of 8 cm long chord of the same circle from the centre.
  3. In a triangle PQR, if $\angle P + \angle R = 150^\circ$ and $\angle P + 3\angle Q = 170^\circ$, then $\angle P$ is equal to :
  4. PQR is a triangle. The bisectors of the internal angle $\angle Q$ and external angle $\angle R$ intersect at M. If $\angle QMR = 40^\circ$, then $\angle P$ is :
  5. Find the sum of 8 exterior angles of a 24-sided regular polygon.
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