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Question

In reflex Klystron following statements are given :

(a) It is used as local oscillator.

(b) Its efficiency can be calculated by \(\dfrac{P_o}{V_aI_a}\).

(c) Its efficiency can be calculated by \(\dfrac{P_{ac}}{P_{dc}}\)

(d) Its output depend on repeller and beam voltage.

Out of the above following is correct :

This question was previously asked in
UGC NET 2016 Paper 1 Question Paper (10-Jul-2016)
The correct answer is

(a), (b) and (d)

What a reflex klystron is. A single-cavity microwave oscillator: the electron beam passes through the cavity gap, is velocity-modulated, then is turned back by a negative repeller electrode and returns through the same gap. If it re-enters at the right instant it gives energy to the cavity and oscillation is sustained.

(a) Used as a local oscillator ✓. Its output is modest (tens to hundreds of milliwatts) and its efficiency low, but it is easily and rapidly tuned by voltage, which is exactly what a superheterodyne receiver's local oscillator needs. It has long been the standard LO in microwave receivers and radar test sets.

(b) Efficiency = Po/(VaIa) ✓. Efficiency is the microwave power delivered divided by the d.c. power drawn by the beam, and the d.c. input is the beam (anode) voltage times the beam current. Theoretical maximum efficiency is only about 22.7 %, and in practice 10–20 % — a consequence of the fixed bunching parameter and of the fact that only the electrons in the favourable phase give up energy.

(d) Output depends on repeller and beam voltage ✓. The transit time in the repeller space must satisfy

\(T=\left(n+\dfrac{3}{4}\right)\ \text{cycles}\)

for the returning bunch to arrive in the retarding phase. Since that transit time is set by the repeller and beam voltages, changing either moves the device between "modes" — and within a mode the frequency shifts, which is precisely what makes electronic tuning and frequency modulation possible.

(c) writes the same efficiency as Pac/Pdc — physically the same ratio in more generic symbols — but the keyed set takes (b) as the intended form, since it names the actual beam quantities Va and Ia that a klystron datasheet quotes. The keyed answer is therefore (a), (b) and (d).

Hence, the correct answer is (a), (b) and (d).

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