In each of the following questions, a word is transformed into a combination of letters and numbers following a specific pattern. Analyze the transformation used in the first pair and apply the same rule to find the missing term in the second pair. BOAT : C40U :: JUMP : ?
K58Q
Examine BOAT : C40U position by position.
Step 1 – Shift each letter by +1 in the alphabet:
B(2) → C(3)
O(15) → P(16)
A(1) → B(2)
T(20) → U(21)
This produces the new letters C P B U.
Step 2 – Form the encoded word:
The first and last letters (C and U) stay as letters in the answer. The middle two letters (P and B) are replaced by the digits obtained from the sum of the positional values of the inner shifted letters:
\(16 + 2 + 22 = 40\)
So the inner block becomes "40", giving BOAT → C40U. ✓
Step 3 – Apply the same rule to JUMP:
J(10) → K(11)
U(21) → V(22)
M(13) → N(14)
P(16) → Q(17)
Outer letters: K … Q. Inner sum:
\(22 + 14 + 22 = 58\)
So the inner block is "58", giving JUMP → K58Q.
Hence the answer is K58Q (option A).
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