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Question

In each of the following questions, a word is transformed into another word by applying a specific alphabetical pattern to each of its letters. Identify the logic used in the first pair and apply the same logic to the second word to determine the correct answer.
FROST: ITQSR :: CHALK: ?

This question was previously asked in
SSC Stenographer 2025 Question Paper (06-Aug-2025) Shift 2
The correct answer is
FJCLI

Solving the Alphabetical Pattern Coding Question

This question requires us to decipher a specific alphabetical pattern used to transform one word into another. Once we identify this logic using the first pair ("FROST" transforming into "ITQSR"), we must apply the identical pattern to the second word ("CHALK") to find its corresponding transformed word.

Analyzing the First Word Pair: FROST to ITQSR

To uncover the pattern, we'll compare each letter of "FROST" with its corresponding letter in "ITQSR". We can determine the shift by looking at the position of each letter in the English alphabet (where A=1, B=2, ..., Z=26).

Original Letter Original Position Transformed Letter Transformed Position Shift Calculation
F 6 I 9 $9 - 6 = +3$
R 18 T 20 $20 - 18 = +2$
O 15 Q 17 $17 - 15 = +2$
S 19 S 19 $19 - 19 = +0$
T 20 R 18 $18 - 20 = -2$

The analysis reveals a specific sequence of shifts applied to the letters:

  • The first letter experiences a shift of +3.
  • The second letter experiences a shift of +2.
  • The third letter experiences a shift of +2.
  • The fourth letter experiences a shift of +0 (no change).
  • The fifth letter experiences a shift of -2.

Thus, the pattern is a sequence of shifts: +3, +2, +2, +0, -2.

Applying the Pattern to the Second Word: CHALK

Now, we apply this exact sequence of shifts (+3, +2, +2, +0, -2) to each letter of the word "CHALK" in order.

Original Letter Original Position Pattern Applied Resulting Position Calculation Transformed Letter
C 3 +3 $3 + 3 = 6$ F
H 8 +2 $8 + 2 = 10$ J
A 1 +2 $1 + 2 = 3$ C
L 12 +0 $12 + 0 = 12$ L
K 11 -2 $11 - 2 = 9$ I

By applying the pattern to each letter:

  • C becomes F (C + 3)
  • H becomes J (H + 2)
  • A becomes C (A + 2)
  • L remains L (L + 0)
  • K becomes I (K - 2)

Combining these results gives us the transformed word "FJCLI".

Final Result

The word "CHALK", when transformed using the specific alphabetical pattern derived from "FROST" to "ITQSR", becomes "FJCLI".

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Similar Questions

  1. In a certain code language, ‘BREATHE’ is coded as 70 and ‘TRIUMPH’ is coded as 135.How will ‘TRAGEDY’ be coded in the same language?
  2. In a certain code language, 'LEMON' is coded as OQPIQ and 'BASIL' is coded as MKVEG. How will 'CHILI' be coded in the same language?
  3. Four of the following five are alike in a certain way and hence form a group. Which is the one that does not belong to that group?
    1. BRISK: DTKUO
    2. CLOUD: ENQUF
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  4. In each of the following question, a pair of words (letter sequences) is given on the left-hand side of the double colon (::), which follows a certain alphabetical pattern. Identify the logic in the first pair and apply the same logic to the third word to find the correct corresponding word from the options.
    FOX: FPY:: JAR:?
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Important Questions from Coding decoding

  1. The letters from A to Z are numbered from 1 to 26 respectively. If GHI = 1578 and DEF = 912, then what is ABC equal to?

  2. What is the missing term in the following? ACPQ : BESU:: MNGI: @

  3. what is the largest number among the following?

  4. What is the greatest length x such that 3 ½ m and 8 ¾ m are integral multiples of x?

  5. In a certain code, '256' means 'red colour chalk', '589' means 'green colour flower' and '254' means 'white colour chalk'. The digit in the code that indicates `white' is

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