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Question

In a triangle ABC, a – 2b + c = 0. The value of \(\cot \left( {\frac{A}{2}} \right)\cot \left( {\frac{C}{2}} \right)\) is

This question was previously asked in
NDA I 2017 GAT Previous Year Paper (23-Apr-2017)
The correct answer is

3

Concept:

Properties of Triangle:

If the three sides a, b, and c are the sides of a triangle,\({\rm{\Delta }} = {\rm{\;}}\sqrt {{\rm{s}}\left( {{\rm{s}} - {\rm{a}}} \right)\left( {{\rm{s}} - {\rm{b}}} \right)\left( {{\rm{s}} - {\rm{c}}} \right)}\)where \({\rm{s}} = \frac{{{\rm{a}} + {\rm{b}} + {\rm{c}}}}{2}\) where

S = semi-perimeter of a triangle

Semi-angle formulas of a triangle:

In Δ ABC 

  • \(\sin \left( {\frac{{\rm{A}}}{2}} \right) = {\rm{\;}}\sqrt {\frac{{({\rm{s}} - {\rm{b}}(\left( {{\rm{s}} - {\rm{c}}} \right)}}{{{\rm{bc}}}}}\)
  • \(\cos \left( {\frac{{\rm{A}}}{2}} \right) = {\rm{\;}}\sqrt {\frac{{{\rm{s}}\left( {{\rm{s}} - {\rm{a}}} \right)}}{{{\rm{bc}}}}}\)
  • \(\tan \left( {\frac{{\rm{A}}}{2}} \right) = {\rm{\;}}\sqrt {\frac{{\left( {{\rm{s}} - {\rm{b}}} \right)\left( {{\rm{s}} - {\rm{c}}} \right)}}{{{\rm{s}}\left( {{\rm{s}} - {\rm{a}}} \right)}}}\)

 

Calculation:

It is given that, a – 2b + c = 0

⇒ a + c = 2b

As we know that the semi-perimeter S of a triangle = (a + b + c)/2

⇒ s = (2b + b) /2 = 3b/2

As we know that

\({\rm{Cot\;}}\left( {\frac{{\rm{A}}}{2}} \right) = \sqrt {\frac{{{\rm{s}}\left( {{\rm{s}} - {\rm{a\;}}} \right)}}{{\left( {{\rm{s}} - {\rm{b}}} \right)\left( {{\rm{s}} - {\rm{c}}} \right)}}} ,\cot \left( {\frac{{\rm{c}}}{2}} \right) = {\rm{\;}}\sqrt {\frac{{{\rm{s}}\left( {{\rm{s}} - {\rm{c}}} \right)}}{{\left( {{\rm{s}} - {\rm{a}}} \right)\left( {{\rm{s}} - {\rm{b}}} \right)}}}\)

\(\Rightarrow \cot \left( {\frac{{\rm{A}}}{2}} \right)\cot \left( {\frac{{\rm{c}}}{2}} \right) = {\rm{\;}}\sqrt {\frac{{{\rm{s}}\left( {{\rm{s}} - {\rm{a\;}}} \right)}}{{\left( {{\rm{s}} - {\rm{b}}} \right)\left( {{\rm{s}} - {\rm{c}}} \right)}}} \sqrt {\frac{{{\rm{s}}\left( {{\rm{s}} - {\rm{c}}} \right)}}{{\left( {{\rm{s}} - {\rm{a}}} \right)\left( {{\rm{s}} - {\rm{b}}} \right)}}}\)

\(\Rightarrow \cot \left( {\frac{{\rm{A}}}{2}} \right)\cot \left( {\frac{{\rm{c}}}{2}} \right) = {\rm{\;}}\sqrt {\frac{{{{\rm{s}}^2}}}{{{{\left( {{\rm{s}} - {\rm{b}}} \right)}^2}}}}\)

\(\Rightarrow \cot \left( {\frac{{\rm{A}}}{2}} \right)\cot \left( {\frac{{\rm{c}}}{2}} \right) = \frac{{\rm{s}}}{{\left( {{\rm{s}} - {\rm{b}}} \right)}}\)

\(\Rightarrow \cot \left( {\frac{{\rm{A}}}{2}} \right)\cot \left( {\frac{{\rm{c}}}{2}} \right) = \frac{{\frac{{3{\rm{b}}}}{2}}}{{\frac{{3{\rm{b}}}}{2} - {\rm{b}}}} = 3\)

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Similar Questions

  1. In a triangle ABC, a = (1 + √3) cm, b = 2 cm and angle C = 60°, then the other two angles are

  2. Consider the following statements :

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    Which of the statements given above is/are correct ?

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  6. Consider the following statements:

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Important Questions from Properties of Triangles

  1. In a triangle ABC, a = (1 + √3) cm, b = 2 cm and angle C = 60°, then the other two angles are

  2. Which of the following measures can form a triangle?

  3. Which of the following cannot be the sides of a triangle?

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