The problem involves calculating the correction for a specific line in a closed traverse based on a given closing error. A closed traverse ensures that the survey path returns to the starting point. The closing error here is +0.5°, originating from the bearings of the last line, indicating a misclosure in the angle measurements.
The total angle misclosure needs to be compensated. The total correction required for the angles is the negative of the closing error.
Different methods exist for distributing this correction. Assuming a method where the correction is proportional to the sequence number of the line is required to match the options provided.
The correction ($C_i$) for the $i$-th line is calculated proportionally based on its sequence number ($i$) relative to the total number of sides ($n$). The formula used, derived from analyzing the options and the likely intended method, is:
$ C_i = \frac{i}{n} \times (\text{Total Correction Required}) $
For the fourth line ($i=4$) in a five-sided traverse ($n=5$):
$ C_4 = \frac{4}{5} \times (-0.5^\circ) $
$ C_4 = -0.4^\circ $
Convert the correction from decimal degrees to degrees and minutes:
$ -0.4^\circ = -0.4 \times 60 \text{ minutes} = -24 \text{ minutes} $
Thus, the correction for the fourth line is -0°24′.
The angular misclosure of the closed-loop traverse shown in the figure is _____________ ° (Answer in decimal degrees and rounded off to three decimal places)
| Station | Easting (m) | Northing (m) |
|---|---|---|
| B | 11054.09 | 9484.37 |
| C | 10827.62 | 10112.15 |
While carrying out a traverse survey ABCDA' using a theodolite with the originating station A, the departures and latitudes of the lines, as obtained, are shown in the following figure (not drawn to scale). It is seen that, due to the observational errors, the originating station A and its computed station A' are not the same. For this survey, the 'closing error' in m is
