In a class of 100 students, there are 70 boys whose average marks in a subject are 75. If average marks of the complete class is 72, then what is the average marks of the girls?
65
This problem involves calculating the average marks of a specific group (girls) within a larger group (the class), given the total class size, the average marks of the entire class, and the count and average marks of another subgroup (boys).
The key concept here is the relationship between total marks, the number of students, and the average marks. The formula for average is:
\[\text{Average Marks} = \frac{\text{Total Marks}}{\text{Number of Students}}\]
From this, we can derive:
\[\text{Total Marks} = \text{Average Marks} \times \text{Number of Students}\]
We are given the number of boys and their average marks.
Using the formula for total marks:
\[\text{Total Marks of Boys} = \text{Average Marks of Boys} \times \text{Number of Boys}\]
\[\text{Total Marks of Boys} = 75 \times 70\]
\[\text{Total Marks of Boys} = 5250\]
So, the total marks scored by all the boys in the class is 5250.
We are given the total number of students in the class and the average marks of the complete class.
Using the formula for total marks:
\[\text{Total Marks of Class} = \text{Average Marks of Class} \times \text{Total Number of Students}\]
\[\text{Total Marks of Class} = 72 \times 100\]
\[\text{Total Marks of Class} = 7200\]
The total marks scored by all 100 students in the class is 7200.
The total marks of the class is the sum of the total marks of the boys and the total marks of the girls.
\[\text{Total Marks of Class} = \text{Total Marks of Boys} + \text{Total Marks of Girls}\]
We can rearrange this to find the total marks of the girls:
\[\text{Total Marks of Girls} = \text{Total Marks of Class} - \text{Total Marks of Boys}\]
Using the values we calculated in the previous steps:
\[\text{Total Marks of Girls} = 7200 - 5250\]
\[\text{Total Marks of Girls} = 1950\]
The total marks scored by all the girls is 1950.
The total number of students in the class is the sum of the number of boys and the number of girls.
\[\text{Total Students} = \text{Number of Boys} + \text{Number of Girls}\]
We can rearrange this to find the number of girls:
\[\text{Number of Girls} = \text{Total Students} - \text{Number of Boys}\]
Using the given values:
\[\text{Number of Girls} = 100 - 70\]
\[\text{Number of Girls} = 30\]
There are 30 girls in the class.
Now we have the total marks of the girls and the number of girls. We can use the average formula:
\[\text{Average Marks of Girls} = \frac{\text{Total Marks of Girls}}{\text{Number of Girls}}\]
Using the values calculated in Steps 3 and 4:
\[\text{Average Marks of Girls} = \frac{1950}{30}\]
\[\text{Average Marks of Girls} = 65\]
The average marks of the girls in the subject is 65.
| Group | Number of Students | Average Marks | Total Marks |
|---|---|---|---|
| Boys | 70 | 75 | \(70 \times 75 = 5250\) |
| Girls | \(100 - 70 = 30\) | ? | \(7200 - 5250 = 1950\) |
| Complete Class | 100 | 72 | \(100 \times 72 = 7200\) |
Using the values from the table for girls:
\[\text{Average Marks of Girls} = \frac{\text{Total Marks of Girls}}{\text{Number of Girls}} = \frac{1950}{30} = 65\]
| Concept | Formula |
|---|---|
| Average | \[\text{Average} = \frac{\text{Sum of all values}}{\text{Count of values}}\] |
| Sum of values (Total) | \[\text{Sum} = \text{Average} \times \text{Count}\] |
| Count | \[\text{Count} = \frac{\text{Sum of all values}}{\text{Average}}\] |
| Combined Average | \[\text{Combined Average} = \frac{(\text{Avg}_1 \times \text{Count}_1) + (\text{Avg}_2 \times \text{Count}_2) + ...}{\text{Count}_1 + \text{Count}_2 + ...}\] |
The average, also known as the mean, is a fundamental concept in statistics used to represent a typical value in a set of numbers. It is calculated by summing all the values in a set and then dividing by the number of values.
In this problem, we used the concept of weighted average implicitly. The class average is a weighted average of the boys' average and the girls' average, weighted by the number of boys and girls respectively. The formula for the class average could be written as:
\[\text{Class Average} = \frac{(\text{Boys Average} \times \text{Number of Boys}) + (\text{Girls Average} \times \text{Number of Girls})}{\text{Number of Boys} + \text{Number of Girls}}\]
Plugging in the known values:
\[72 = \frac{(75 \times 70) + (\text{Girls Average} \times 30)}{100}\]
\[72 \times 100 = (75 \times 70) + (\text{Girls Average} \times 30)\]
\[7200 = 5250 + (\text{Girls Average} \times 30)\]
\[7200 - 5250 = \text{Girls Average} \times 30\]
\[1950 = \text{Girls Average} \times 30\]
\[\text{Girls Average} = \frac{1950}{30} = 65\]
This confirms the result obtained through the step-by-step calculation of total marks. Understanding how to calculate total sums from averages and vice versa is crucial for solving such problems efficiently.
If the average of 9 consecutive positive integers is 55, then what is the largest integer?
The arithmetic mean of 11 observations is 11. The arithmetic mean of the first 6 observations is 10.5 and the arithmetic mean of the last 6 observations is 11.5. What is the sixth observation?
A cricketer has certain average of 10 innings. In the 11 th inning, he scored 108 runs, thereby increasing his average by 6 runs. What is his new average?
The average of 50 consecutive natural numbers is x. What will be the new average when the next four numbers are also included?
Consider two-digit numbers which remain the same when the digits interchange their positions. What is the average of such two-digit numbers?
Mean marks of 50 students were found to be 78.4. But later it was detected that 95 was misread as 59 and 25 was misread as 52. What is the difference between correct mean and incorrect mean?
What is the arithmetic mean of P and Q ?
The arithmetic mean of two numbers is 10 and their geometric mean is 8. What are the two numbers?
A small company pays each of its 5 category ‘C’ workers Rs. 20,000, each of its 3 category ‘B’ workers Rs. 25,000 and a category ‘A’ worker Rs. 65,000. The number of workers earning less than the mean salary is
Consider the following distribution
Class | Frequency |
0 - 20 | 17 |
20 - 40 | 28 |
40 - 60 | 32 |
60 - 80 | F |
80 - 100 | 19 |
If the mean of the above distribution is 50 then what is the value of f?
Average of 40 numbers is 71, if the number 100 replaced by 140, then average is increased by
The captain of a football team of 11 members is 28 years old and the goalkeeper is 4 years older than him. If the ages of these two are removed, then the average age of the remaining players is two years less than the average age of the whole team. What is the average age of the team?
There are two Classes A and B having 25 and 30 students respectively. In Class-A the highest score is 21 and lowest score is 17. In Class-B the highest score is 30 and lowest score is 22. Four students are shifted from Class-A to Class-B.
Consider the following statements:
1. The average score of Class-B will definitely decrease.
2. The average score of Class-A will definitely increase.
Which of the above statements is/are correct?
The average weight of A, B, Cis 40 kg, the average weight of B, D, Eis 42 kg and the weight of Fis equal to that of B. What is the average weight of A, B, C, D, Eand F?
A cow costs more than 4 goats but less than 5 goats. If a goat costs between Rs. 600 and Rs. 800, which of the following is a most valid conclusion?