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Question

In a circle, a 14 cm long chord is at 24 cm from the centre of the circle. Find the length of the radius of the circle.

This question was previously asked in
SSC CGL 2023 (Tier-II) Paper 1 Previous Year Paper (26-Oct-2023) (Shift-1)
The correct answer is

25 cm

Finding the Radius of a Circle Given Chord Length and Distance from Center

This problem involves understanding the relationship between the radius of a circle, a chord within the circle, and the perpendicular distance from the center of the circle to that chord.

In a circle, a chord is a line segment connecting two points on the circumference. The distance from the center to the chord is the length of the perpendicular segment from the center to the chord.

A key property in circle geometry is that the perpendicular from the center of a circle to a chord bisects the chord. This means it cuts the chord into two equal halves.

Let's break down the given information:

  • Length of the chord = 14 cm
  • Distance from the center to the chord = 24 cm

Since the perpendicular from the center bisects the chord, half the length of the chord will be:

\( \text{Half chord length} = \frac{14 \text{ cm}}{2} = 7 \text{ cm} \)

Now, consider the right-angled triangle formed by:

  • The radius of the circle (hypotenuse)
  • Half the length of the chord (one leg)
  • The distance from the center to the chord (the other leg)

Let \( r \) be the radius of the circle. According to the Pythagorean theorem, in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Applying the Pythagorean theorem:

\( r^2 = (\text{Half chord length})^2 + (\text{Distance from center})^2 \)

\( r^2 = (7 \text{ cm})^2 + (24 \text{ cm})^2 \)

\( r^2 = 49 \text{ cm}^2 + 576 \text{ cm}^2 \)

\( r^2 = 625 \text{ cm}^2 \)

To find the radius \( r \), we take the square root of 625:

\( r = \sqrt{625 \text{ cm}^2} \)

\( r = 25 \text{ cm} \)

Therefore, the length of the radius of the circle is 25 cm.

Steps to Calculate Circle Radius

  1. Identify the given chord length and the distance from the circle's center to the chord.
  2. Calculate half of the chord length, as the perpendicular from the center bisects the chord.
  3. Recognize that the radius, half-chord, and distance from the center form a right-angled triangle with the radius as the hypotenuse.
  4. Apply the Pythagorean theorem (\( a^2 + b^2 = c^2 \)), where \( a \) is half the chord length, \( b \) is the distance from the center, and \( c \) is the radius.
  5. Solve the equation for the radius.

Revision Table: Circle Geometry Facts

Term Definition Relevance to Problem
Circle Set of points equidistant from a central point. The figure being discussed.
Radius Distance from the center to any point on the circle. What we need to find.
Chord A line segment connecting two points on the circle. Given length is 14 cm.
Distance from Center to Chord Length of the perpendicular segment from the center to the chord. Given distance is 24 cm.
Pythagorean Theorem \( a^2 + b^2 = c^2 \) in a right triangle. Essential for solving the problem.

Additional Information: Pythagorean Triples

A Pythagorean triple is a set of three positive integers \( a \), \( b \), and \( c \), such that \( a^2 + b^2 = c^2 \). These triples represent the side lengths of a right-angled triangle. Common Pythagorean triples can help quickly identify solutions in geometry problems involving right triangles without lengthy calculations.

Examples of Pythagorean triples include:

  • (3, 4, 5)
  • (5, 12, 13)
  • (7, 24, 25)
  • (8, 15, 17)

In this problem, we had legs of length 7 cm and 24 cm. Recognizing that (7, 24, 25) is a Pythagorean triple allows us to quickly see that the hypotenuse (the radius) must be 25 cm.

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Similar Questions

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  2. AB is the diameter of a circle with centre O. P be a point on it. If ∠AOP = 95°, then ∠OBP __________.

  3. If the area of a circle is 616 cm2 and a chord XY = 10 cm, then find the perpendicular distance from the center of the circle to the chord XY.  

  4. An arc of length 23.1 cm subtends an 18° angle at the centre. What is the area of the circle? [Use \(π = \frac{22}{7}\)]

  5. Find the area of the sector of a circle with radius 5 cm and angle 60° (rounded off to one decimal).

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  7. Two circles of radii 10 cm and 5 cm touch each other externally at a point A. PQ Is the direct common tangent of those two circles of centres O1 and O2 , respectively. The length of PQ is equal to:

  8. Two circles of same radius 6 cm, intersect each other at P and Q. If PQ = 10 cm, then what is the distance between the centres of the two circles?

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Important Questions from Circles, Chords and Tangents

  1. If a tangent to a circle from a point P meets the circle at A with AP = 15 cm. Given that the radius of the circle is 8 cm, find the distance of P from the centre of the circle.

  2. In a circle with a radius of 10 cm. XY and PQ are two parallel chords 12 cm and 16 cm in length, respectively. The two chords are situated on the opposite sides of the centre. The distance between the chords is:

  3. Find the equation of the tangents to the circle x2 + y2 = 9 at x = 2.

  4. If a chord of length 24 cm is at a distance of 5 cm from centre, then find the radius of the circle.

  5. Let \( C_1 \) and \( C_2 \) be two circles which do not externally touch and intersect each other and \( O_1 \), and \( O_2 \) be the centers of the circles, respectively. Let AB be the common transverse tangent to the circles such that P, Q are the points of tangency respectively to \( C_1 \), \( C_2 \). Let R be the point of intersection of \( O_1 O_2 \) and AB. If \( \angle PO_1R = 60^\circ \), find \( \angle QO_2R \) and \( \angle QRO_2 \) respectively.

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