In a circle, a 14 cm long chord is at 24 cm from the centre of the circle. Find the length of the radius of the circle.
25 cm
This problem involves understanding the relationship between the radius of a circle, a chord within the circle, and the perpendicular distance from the center of the circle to that chord.
In a circle, a chord is a line segment connecting two points on the circumference. The distance from the center to the chord is the length of the perpendicular segment from the center to the chord.
A key property in circle geometry is that the perpendicular from the center of a circle to a chord bisects the chord. This means it cuts the chord into two equal halves.
Let's break down the given information:
Since the perpendicular from the center bisects the chord, half the length of the chord will be:
\( \text{Half chord length} = \frac{14 \text{ cm}}{2} = 7 \text{ cm} \)
Now, consider the right-angled triangle formed by:
Let \( r \) be the radius of the circle. According to the Pythagorean theorem, in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Applying the Pythagorean theorem:
\( r^2 = (\text{Half chord length})^2 + (\text{Distance from center})^2 \)
\( r^2 = (7 \text{ cm})^2 + (24 \text{ cm})^2 \)
\( r^2 = 49 \text{ cm}^2 + 576 \text{ cm}^2 \)
\( r^2 = 625 \text{ cm}^2 \)
To find the radius \( r \), we take the square root of 625:
\( r = \sqrt{625 \text{ cm}^2} \)
\( r = 25 \text{ cm} \)
Therefore, the length of the radius of the circle is 25 cm.
| Term | Definition | Relevance to Problem |
|---|---|---|
| Circle | Set of points equidistant from a central point. | The figure being discussed. |
| Radius | Distance from the center to any point on the circle. | What we need to find. |
| Chord | A line segment connecting two points on the circle. | Given length is 14 cm. |
| Distance from Center to Chord | Length of the perpendicular segment from the center to the chord. | Given distance is 24 cm. |
| Pythagorean Theorem | \( a^2 + b^2 = c^2 \) in a right triangle. | Essential for solving the problem. |
A Pythagorean triple is a set of three positive integers \( a \), \( b \), and \( c \), such that \( a^2 + b^2 = c^2 \). These triples represent the side lengths of a right-angled triangle. Common Pythagorean triples can help quickly identify solutions in geometry problems involving right triangles without lengthy calculations.
Examples of Pythagorean triples include:
In this problem, we had legs of length 7 cm and 24 cm. Recognizing that (7, 24, 25) is a Pythagorean triple allows us to quickly see that the hypotenuse (the radius) must be 25 cm.
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