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Question

Find the area of the sector of a circle with radius 5 cm and angle 60° (rounded off to one decimal).

This question was previously asked in
SSC CGL 2023 (Tier-II) Paper 1 Previous Year Paper (26-Oct-2023) (Shift-1)
The correct answer is

13.1 cm2

Finding the Area of a Circle Sector Explained

The question asks us to find the area of a sector of a circle given its radius and the central angle. A sector of a circle is the portion of a disk enclosed by two radii and an arc. Its area is a fraction of the entire circle's area, determined by the ratio of the sector's central angle to the total angle in a circle (360 degrees or \(2\pi\) radians).

Formula for Area of a Sector

The area of a sector can be calculated using the formula:

$$ \text{Area of Sector} = \frac{\theta}{360^\circ} \times \pi r^2 $$

Where:

  • \(\theta\) is the central angle of the sector in degrees.
  • \(r\) is the radius of the circle.
  • \(\pi\) is a mathematical constant, approximately 3.14159.

Applying the Formula to the Given Problem

We are given:

  • Radius, \(r = 5 \text{ cm}\)
  • Central angle, \(\theta = 60^\circ\)

Substitute these values into the formula:

$$ \text{Area} = \frac{60^\circ}{360^\circ} \times \pi (5 \text{ cm})^2 $$

First, simplify the fraction representing the ratio of the angle to the full circle:

$$ \frac{60^\circ}{360^\circ} = \frac{1}{6} $$

Next, calculate the square of the radius:

$$ (5 \text{ cm})^2 = 25 \text{ cm}^2 $$

Now, substitute these simplified values back into the area formula:

$$ \text{Area} = \frac{1}{6} \times \pi \times 25 \text{ cm}^2 $$

$$ \text{Area} = \frac{25\pi}{6} \text{ cm}^2 $$

To get a numerical value, use the value of \(\pi\) (approximately 3.14159):

$$ \text{Area} \approx \frac{25 \times 3.14159}{6} \text{ cm}^2 $$

$$ \text{Area} \approx \frac{78.53975}{6} \text{ cm}^2 $$

$$ \text{Area} \approx 13.089958... \text{ cm}^2 $$

Rounding the Result

The question asks for the area rounded off to one decimal place. Rounding 13.089958... to one decimal place gives 13.1 \text{ cm}^2.

Comparison with Options

Let's compare our calculated area with the given options:

  1. 12.8 cm2
  2. 14.1 cm2
  3. 13.1 cm2
  4. 15.1 cm2

Our calculated area, rounded to one decimal place, is 13.1 cm2, which matches option 3.

Quantity Value
Radius (r) 5 cm
Angle (\(\theta\)) 60°
Formula \(\frac{\theta}{360^\circ} \times \pi r^2\)
Calculated Area \(\approx 13.1 \text{ cm}^2\)

Conclusion

Using the formula for the area of a sector, with a radius of 5 cm and a central angle of 60°, the calculated area is approximately 13.09 cm2. When rounded to one decimal place, this becomes 13.1 cm2.

Revision Table: Key Concepts for Area of Sector

Concept Description Formula (Degrees) Formula (Radians)
Circle Area The area of the entire circle. \(\pi r^2\) \(\pi r^2\)
Sector Angle The angle formed by the two radii at the center. \(\theta^\circ\) \(\theta_{rad}\)
Fraction of Circle Ratio of sector angle to total angle. \(\frac{\theta^\circ}{360^\circ}\) \(\frac{\theta_{rad}}{2\pi}\)
Sector Area The area of the portion enclosed by radii and arc. \(\frac{\theta^\circ}{360^\circ} \times \pi r^2\) \(\frac{\theta_{rad}}{2\pi} \times \pi r^2 = \frac{1}{2} r^2 \theta_{rad}\)

Additional Information: Units and Angles

It is crucial to pay attention to the units of the angle when using the area of sector formula. The formula \(\frac{\theta}{360^\circ} \times \pi r^2\) requires the angle \(\theta\) to be in degrees. If the angle is given in radians, the formula becomes \(\frac{\theta_{rad}}{2\pi} \times \pi r^2\), which simplifies to \(\frac{1}{2} r^2 \theta_{rad}\).

In this problem, the angle was given in degrees (60°), so we correctly used the formula involving 360°. The unit for the area is always in square units, matching the unit of the radius (e.g., cm2, m2, in2).

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Similar Questions

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Important Questions from Circles, Chords and Tangents

  1. If a tangent to a circle from a point P meets the circle at A with AP = 15 cm. Given that the radius of the circle is 8 cm, find the distance of P from the centre of the circle.

  2. In a circle with a radius of 10 cm. XY and PQ are two parallel chords 12 cm and 16 cm in length, respectively. The two chords are situated on the opposite sides of the centre. The distance between the chords is:

  3. Find the equation of the tangents to the circle x2 + y2 = 9 at x = 2.

  4. If a chord of length 24 cm is at a distance of 5 cm from centre, then find the radius of the circle.

  5. Let \( C_1 \) and \( C_2 \) be two circles which do not externally touch and intersect each other and \( O_1 \), and \( O_2 \) be the centers of the circles, respectively. Let AB be the common transverse tangent to the circles such that P, Q are the points of tangency respectively to \( C_1 \), \( C_2 \). Let R be the point of intersection of \( O_1 O_2 \) and AB. If \( \angle PO_1R = 60^\circ \), find \( \angle QO_2R \) and \( \angle QRO_2 \) respectively.

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