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Question

An arc of length 23.1 cm subtends an 18° angle at the centre. What is the area of the circle? [Use \(π = \frac{22}{7}\)]

This question was previously asked in
SSC CGL 2023 (Tier-II) Paper 1 Previous Year Paper (26-Oct-2023) (Shift-1)
The correct answer is

16978.50 cm2

Calculating Circle Area from Arc Length and Angle

This problem requires us to find the area of a circle when we are given the length of an arc and the angle it subtends at the centre. We are provided with the arc length, the central angle, and the value of \(\pi\).

Here's how we can solve it:

First, we need to find the radius of the circle using the given arc length and central angle. The formula for the length of an arc is:

\[ \text{Arc Length} = \frac{\theta}{360^\circ} \times 2\pi r \]where:

  • \(\theta\) is the central angle in degrees.
  • \(r\) is the radius of the circle.

We are given:

  • Arc Length = 23.1 cm
  • \(\theta = 18^\circ\)
  • \(\pi = \frac{22}{7}\)

Substitute these values into the arc length formula:

\[ 23.1 = \frac{18}{360} \times 2 \times \frac{22}{7} \times r \]

Simplify the fraction \(\frac{18}{360}\):

\[ \frac{18}{360} = \frac{18 \div 18}{360 \div 18} = \frac{1}{20} \]

Substitute this back into the equation:

\[ 23.1 = \frac{1}{20} \times 2 \times \frac{22}{7} \times r \]

Simplify the multiplication on the right side:

\[ 23.1 = \frac{2}{20} \times \frac{22}{7} \times r \]

\[ 23.1 = \frac{1}{10} \times \frac{22}{7} \times r \]

\[ 23.1 = \frac{22}{70} \times r \]

Now, solve for \(r\):

\[ r = \frac{23.1 \times 70}{22} \]

To make calculation easier, convert 23.1 to a fraction \(\frac{231}{10}\):

\[ r = \frac{231}{10} \times \frac{70}{22} \]

Cancel out common factors:

\[ r = \frac{231}{\cancel{10}} \times \frac{\cancel{70}^7}{22} \]

\[ r = \frac{231 \times 7}{22} \]

Now, divide 231 and 22 by 11:

\[ r = \frac{\cancel{231}^{21} \times 7}{\cancel{22}^2} \]

\[ r = \frac{21 \times 7}{2} = \frac{147}{2} = 73.5 \text{ cm} \]

So, the radius of the circle is 73.5 cm.

Next, we need to find the area of the circle using the formula:

\[ \text{Area} = \pi r^2 \]

Substitute the values of \(\pi\) and \(r\):

\[ \text{Area} = \frac{22}{7} \times (73.5)^2 \]

Substitute \(73.5 = \frac{147}{2}\):

\[ \text{Area} = \frac{22}{7} \times \left(\frac{147}{2}\right)^2 \]

\[ \text{Area} = \frac{22}{7} \times \frac{147 \times 147}{2 \times 2} \]

\[ \text{Area} = \frac{22}{7} \times \frac{147 \times 147}{4} \]

Cancel out common factors. Divide 147 by 7:

\[ \text{Area} = \frac{22}{\cancel{7}^1} \times \frac{\cancel{147}^{21} \times 147}{4} \]

\[ \text{Area} = \frac{22 \times 21 \times 147}{4} \]

Divide 22 and 4 by 2:

\[ \text{Area} = \frac{\cancel{22}^{11} \times 21 \times 147}{\cancel{4}^2} \]

\[ \text{Area} = \frac{11 \times 21 \times 147}{2} \]

Multiply the numbers in the numerator:

\[ 11 \times 21 = 231 \]

\[ 231 \times 147 = 33957 \]

So, the area is:

\[ \text{Area} = \frac{33957}{2} = 16978.5 \text{ cm}^2 \]

The area of the circle is 16978.50 cm2.

Revision Table: Circle Geometry Formulas

Concept Formula Description
Circumference of Circle \(C = 2\pi r\) or \(C = \pi d\) The total distance around the circle.
Area of Circle \(A = \pi r^2\) The space enclosed within the circle.
Arc Length \(L = \frac{\theta}{360^\circ} \times 2\pi r\) The length of a portion of the circle's circumference, defined by a central angle \(\theta\).
Area of Sector \(A_{sector} = \frac{\theta}{360^\circ} \times \pi r^2\) The area of the portion of the circle enclosed by two radii and an arc, defined by a central angle \(\theta\).

Additional Information on Circle Properties

Circles are fundamental shapes in geometry with many interesting properties. Understanding the relationship between the radius, diameter, circumference, area, arc length, and sector area is crucial for solving problems.

  • The radius (\(r\)) is the distance from the center to any point on the circle.
  • The diameter (\(d\)) is the distance across the circle through the center (\(d=2r\)).
  • \(\pi\) (pi) is a mathematical constant approximately equal to 3.14159 or \(\frac{22}{7}\), representing the ratio of a circle's circumference to its diameter.
  • A central angle is an angle whose vertex is the center of the circle and whose sides are radii.
  • The arc subtended by a central angle is the portion of the circle's circumference between the two radii.
  • A sector is the region of a circle bounded by two radii and their intercepted arc. Its area is a fraction of the total circle area, proportional to the central angle.

Remember that angles in formulas are typically given in degrees or radians. The formula used here requires the angle in degrees. If an angle is given in radians, you would convert it (\(180^\circ = \pi \text{ radians}\)) or use the formula for arc length with radians: \(L = r\theta\) (where \(\theta\) is in radians).

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Important Questions from Circles, Chords and Tangents

  1. If a tangent to a circle from a point P meets the circle at A with AP = 15 cm. Given that the radius of the circle is 8 cm, find the distance of P from the centre of the circle.

  2. In a circle with a radius of 10 cm. XY and PQ are two parallel chords 12 cm and 16 cm in length, respectively. The two chords are situated on the opposite sides of the centre. The distance between the chords is:

  3. Find the equation of the tangents to the circle x2 + y2 = 9 at x = 2.

  4. If a chord of length 24 cm is at a distance of 5 cm from centre, then find the radius of the circle.

  5. Let \( C_1 \) and \( C_2 \) be two circles which do not externally touch and intersect each other and \( O_1 \), and \( O_2 \) be the centers of the circles, respectively. Let AB be the common transverse tangent to the circles such that P, Q are the points of tangency respectively to \( C_1 \), \( C_2 \). Let R be the point of intersection of \( O_1 O_2 \) and AB. If \( \angle PO_1R = 60^\circ \), find \( \angle QO_2R \) and \( \angle QRO_2 \) respectively.

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