In a certain code language, 'HUT’ is coded as '55' and 'MAT' is coded as '40'. How will 'BIB' be coded in that language?
19
This problem involves understanding a simple code language where words are represented by numbers. We are given two examples to figure out the rule, and then we apply that rule to a third word.
In many coding and decoding problems, letters are assigned numerical values based on their position in the English alphabet. A is typically 1, B is 2, C is 3, and so on, up to Z which is 26. Let's list the values for the letters in our given words:
Let's see if the code is related to the sum of the positional values of the letters in each word.
The letters are H, U, T. Their positional values are 8, 21, and 20.
Sum of positional values for HUT = \(\text{Value(H)} + \text{Value(U)} + \text{Value(T)}\)
Sum = \(8 + 21 + 20 = 49\)
The given code for HUT is 55.
Difference = Given Code - Sum of values = \(55 - 49 = 6\)
The letters are M, A, T. Their positional values are 13, 1, and 20.
Sum of positional values for MAT = \(\text{Value(M)} + \text{Value(A)} + \text{Value(T)}\)
Sum = \(13 + 1 + 20 = 34\)
The given code for MAT is 40.
Difference = Given Code - Sum of values = \(40 - 34 = 6\)
In both cases, the given code is 6 more than the sum of the positional values of the letters. This suggests the rule is: Code = Sum of positional values + 6.
Now let's apply this rule to find the code for the word 'BIB'.
The letters are B, I, B. Their positional values are 2, 9, and 2.
Sum of positional values for BIB = \(\text{Value(B)} + \text{Value(I)} + \text{Value(B)}\)
Sum = \(2 + 9 + 2 = 13\)
Using the rule (Code = Sum of values + 6):
Code for BIB = \(13 + 6 = 19\)
Therefore, 'BIB' will be coded as '19' in this language.
| Word | Letters | Positional Values | Sum of Values | Code | Rule Check |
|---|---|---|---|---|---|
| HUT | H, U, T | 8, 21, 20 | \(8 + 21 + 20 = 49\) | 55 | \(49 + 6 = 55\) (Matches) |
| MAT | M, A, T | 13, 1, 20 | \(13 + 1 + 20 = 34\) | 40 | \(34 + 6 = 40\) (Matches) |
| BIB | B, I, B | 2, 9, 2 | \(2 + 9 + 2 = 13\) | ? | \(13 + 6 = 19\) |
The calculated code for BIB is 19.
Reviewing the steps taken to solve the coding problem:
Coding and decoding questions are common in reasoning sections of competitive exams. They test your ability to find patterns. Some common types include:
This problem is an example of Number Coding based on positional values with an added constant.
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