Coding Decode Reasoning for 'my vintage house'

This question involves decoding a simple substitution cipher where words are represented by two-letter codes. We need to find the codes for 'my', 'vintage', and 'house' based on the provided examples.

Step 1: Identify Codes for Common Words

We compare the given coded phrases to find common words and their corresponding codes.

• 'find my car' is coded as 'mi co kh'
• 'black vintage car' is coded as 'co ne ve'
• 'find black house' is coded as 'ne kh sa'

By comparing the first two phrases, 'car' is common, and 'co' is the common code. Thus, car = co.

By comparing the first and third phrases, 'find' is common, and 'kh' is the common code. Thus, find = kh.

By comparing the second and third phrases, 'black' is common, and 'ne' is the common code. Thus, black = ne.

Step 2: Determine Codes for Remaining Words

Now we use the identified codes to find the codes for the remaining words.

• In 'find my car' ('mi co kh'), since 'find' = 'kh' and 'car' = 'co', the remaining word 'my' must correspond to the remaining code 'mi'. So, my = mi.
• In 'black vintage car' ('co ne ve'), since 'black' = 'ne' and 'car' = 'co', the remaining word 'vintage' must correspond to the remaining code 've'. So, vintage = ve.
• In 'find black house' ('ne kh sa'), since 'find' = 'kh' and 'black' = 'ne', the remaining word 'house' must correspond to the remaining code 'sa'. So, house = sa.

Step 3: Find the Code for 'my vintage house'

We need the codes for 'my', 'vintage', and 'house'. From Step 2, we have:

• my = mi
• vintage = ve
• house = sa

Combining these codes gives us the set {mi, ve, sa}. The phrase 'my vintage house' can be coded by any arrangement of these codes. Option 4 provides these codes in the order 'sa mi ve'.