Decoding the Coded Language

The problem involves deciphering a simple substitution code based on given phrases. We need to find the code word for 'Ram'.

Given phrases:

• 'Ram is boy' is written as 'qaz wsx edc'
• 'boy has car' is written as 'plm qaz ijb'
• 'car is blue' is written as 'edc ijb ftb'

Step 1: Identify Common Words and Codes

Compare the first two phrases:

• 'Ram is boy' -> 'qaz wsx edc' (Original coding has 'qaz wsx edc')
• 'boy has car' -> 'plm qaz ijb'

The common word is 'boy'. The common code word between 'qaz wsx edc' and 'plm qaz ijb' is 'qaz'. Therefore, 'boy' = 'qaz'.

Compare the first and third phrases:

• 'Ram is boy' -> 'qaz wsx edc'
• 'car is blue' -> 'edc ijb ftb'

The common word is 'is'. The common code word between 'qaz wsx edc' and 'edc ijb ftb' is 'edc'. Therefore, 'is' = 'edc'.

Compare the second and third phrases:

• 'boy has car' -> 'plm qaz ijb'
• 'car is blue' -> 'edc ijb ftb'

The common word is 'car'. The common code word between 'plm qaz ijb' and 'edc ijb ftb' is 'ijb'. Therefore, 'car' = 'ijb'.

Step 2: Determine the Code for 'Ram'

Now, look at the first phrase again:

• 'Ram is boy' -> 'wsx qaz edc' (Reordered codes for clarity based on deductions)

We know 'is' = 'edc' and 'boy' = 'qaz'. The remaining word in the phrase is 'Ram', and the remaining code is 'wsx'.

Therefore, 'Ram' = 'wsx'.

Step 3: Verify Other Words (Optional)

From 'boy has car' -> 'plm qaz ijb', since 'boy'='qaz' and 'car'='ijb', then 'has' = 'plm'.

From 'car is blue' -> 'edc ijb ftb', since 'is'='edc' and 'car'='ijb', then 'blue' = 'ftb'.

The deductions are consistent.

Conclusion

The code word for 'Ram' is 'wsx'.