In a certain code language, 'A + B' means 'A is the mother of B'; 'A - B' means 'A is the brother of B'; 'A × B' means 'A is the sister of B' and 'A ÷ B' means 'A is the daughter of B'. Based on the above, if \(J + K ÷ L - T × R\). then how is J related to L?
Wife
Code key: ‘+’ → mother, ‘–’ → brother, ‘×’ → sister, ‘÷’ → daughter.
The chain is \(J + K ÷ L - T × R\). Decode it from right to left or left to right, keeping each pair together.
- K ÷ L means “K is the daughter of L” ⇒ L is a parent of K.
- J + K means “J is the mother of K”.
Thus J and L are the two parents of the same child K.
- L – T means “L is the brother of T” ⇒ L is male.
Since L is male and a parent of K, L must be K’s father. Consequently, J (the mother) is the wife of L.
Answer → J is L’s wife.
Shortcut tip: When two coded statements give the same child with two different parents, those parents form a couple; then use any gender clue to label husband-wife correctly.
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Important Questions from Blood Relations
Introducing a girl, the boy says, "She is the daughter of my uncle's father's son". How is the girl related to the boy.
A. Niece
B. Daughter-in-law
C. Sister
D. Aunt
'D' is the son of 'F'. 'E' is the sister of 'F', and her son is 'A' and daughter is 'X'. If 'B' is the maternal uncle of 'A'; So how is 'D' related to 'B'?
A. Cousin
B. Nephew
C. Maternal Uncle
D. Brother
Pointing to a girl, Sunil said, "Her mother's brother is the only son of my mother's father and the brother has only one sister". How is the girl's mother related to Sunil?
A. Maternal Aunt
B. Sister
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In a certain code language,
‘A + B’ means ‘A is the mother of B’,
‘A − B’ means ‘A is the daughter of B’,
‘A × B’ means ‘A is the husband of B’,
‘A ÷ B’ means ‘A is the sister of B’.
Based on the above, how is M related to Q if ‘M ÷ N − O × P + Q’?In a certain code language,
A + B means 'A is the son of B',
A - B means 'A is the wife of B',
A × B means 'A is the brother of B' and
A ÷ B means 'A is the daughter of B'.
Based on the above, how is P related to R if 'P × S + M – T + R'?
