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If \(y = \left|\sin\left(\dfrac{\pi}{4} - x\right)\right|\), then what is \(\dfrac{dy}{dx}\) at \(x = \dfrac{\pi}{4}\) equal to?

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NDA 2 2026 GAT Question Paper (13-Sep-2026)
The correct answer is

It does not exist

Let \(u = \sin\left(\dfrac{\pi}{4} - x\right)\); at \(x=\dfrac{\pi}{4}\), \(u=0\) and \(\dfrac{du}{dx} = -\cos\left(\dfrac{\pi}{4}-x\right) = -1\). Since \(u\) changes sign as \(x\) passes through \(\dfrac{\pi}{4}\) while \(\dfrac{du}{dx} \neq 0\) there, the left-hand derivative of \(y=|u|\) is \(-1\) and the right-hand derivative is \(+1\), which are unequal. Hence \(\dfrac{dy}{dx}\) does not exist at \(x=\dfrac{\pi}{4}\).

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