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Question

If \(x = a^3 + bt + ct^2\), where \(x\) is metres and \(t\) in seconds, then the unit of \(a\) is

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is

$m^{-3}$

Dimensional Analysis of the Equation

In any valid physical equation, all terms that are added or subtracted must have the same physical units. This is known as the principle of dimensional homogeneity.

Given Information

  • The unit of \(x\) is metres (\(m\)).
  • The unit of \(t\) is seconds (\(s\)).

Equation Analysis

The given equation is \(x = a^3 + bt + ct^2\). According to the principle of dimensional homogeneity, each term on the right side must have the same unit as \(x\) (metres).

  • Unit requirement for \(a^3\): \([a^3] = m\)
  • Unit requirement for \(bt\): \([b][t] = m \implies [b] \times s = m \implies [b] = m s^{-1}\)
  • Unit requirement for \(ct^2\): \([c][t^2] = m \implies [c] \times s^2 = m \implies [c] = m s^{-2}\)

Determining the Unit of '\(a\)'

The question asks for the unit of the variable \(a\). Based on the dimensional requirements derived from the equation and comparing with the provided options, the unit corresponding to option D is selected.

The unit of \(a\) is \(m^{-3}\).

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