$[M^1L^0T^{-2}A^{-1}]$
To find the dimensional formula for the magnetic flux density \( B \), we need to start from the Lorentz force equation:
\(\vec{F} = q(\vec{v} \times \vec{B})\),
where \( \vec{F} \) is the force, \( q \) is the electric charge, \( \vec{v} \) is velocity, and \( \vec{B} \) is the magnetic flux density.
We need to establish the relationship between these variables in terms of their dimensions:
- Dimensional Formula of Force \( F \):
The force is given by \( F = ma \), where \( m \) is mass and \( a \) is acceleration. Thus, the dimensional formula of force is: [M^1L^1T^{-2}]. - Dimensional Formula of Charge \( q \):
Electric charge can be expressed in terms of current and time: \( q = I \cdot t \). Hence, the dimensional formula of charge is: [A^1T^1]. - Dimensional Formula of Velocity \( v \):
Velocity is given by distance over time: [L^1T^{-1}].
Using the Lorentz force equation, equate the dimensions of both sides:
[M^1L^1T^{-2}] = [A^1T^1] \cdot [L^1T^{-1}] \cdot [B]
Rearrange to find the dimension of \( B \):
[B] = \frac{[M^1L^1T^{-2}]}{[A^1T^1] \cdot [L^1T^{-1}]}
Simplify the expression,
[B] = \frac{[M^1L^1T^{-2}]}{[A^1L^1T^0]}
Cancel out and simplify:
[B] = [M^1L^0T^{-2}A^{-1}]
Thus, the dimensional formula for magnetic flux density \( B \) is correctly given by [M^1L^0T^{-2}A^{-1}].
Therefore, the correct answer is the option:
[M^1L^0T^{-2}A^{-1}].
Important Questions from Dimensional formulae and dimensional equations
LT-2 is the dimension of which of the following quantities?
- The characteristic impedance of free space, $Z_0$, is given by the expression $Z_0 = \sqrt{\frac{\mu_0}{\epsilon_0}}$. If $\mu_0$ represents the magnetic permeability and $\epsilon_0$ represents the electric permittivity, what are the dimensions of $Z_0$?
If \(x = a^3 + bt + ct^2\), where \(x\) is metres and \(t\) in seconds, then the unit of \(a\) is
- The dimensional formula of speed
The dimensions of energy are:
