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Question

If we increase each even digit by "1" and decrease each odd digit by "1" in the number "7846921453" and then arrange all the number in descending order, then what is the sum of the last five digits from the right end after the rearrangement?

This question was previously asked in
SSC CGL 2025 Tier 2 Paper 1 Question Paper (19-Jan-2026)
The correct answer is

35

Digit Transformation and Sum Calculation

Follow these steps to find the required sum:

Step 1: Apply Digit Transformations

Modify each digit in the number "7846921453" based on the rules: increase even digits by 1 and decrease odd digits by 1.

  • 7 (odd) becomes 7 - 1 = 6
  • 8 (even) becomes 8 + 1 = 9
  • 4 (even) becomes 4 + 1 = 5
  • 6 (even) becomes 6 + 1 = 7
  • 9 (odd) becomes 9 - 1 = 8
  • 2 (even) becomes 2 + 1 = 3
  • 1 (odd) becomes 1 - 1 = 0
  • 4 (even) becomes 4 + 1 = 5
  • 5 (odd) becomes 5 - 1 = 4
  • 3 (odd) becomes 3 - 1 = 2

The transformed digits are: 6, 9, 5, 7, 8, 3, 0, 5, 4, 2.

Step 2: Arrange Digits in Descending Order

Sort the transformed digits from largest to smallest (descending order):

9, 8, 7, 6, 5, 5, 4, 3, 2, 0

Step 3: Identify the Last Five Digits (from the right end)

In a descending sequence, the "last five digits from the right end" refers to the five largest digits. These are the first five digits in the sorted list:

9, 8, 7, 6, 5

Step 4: Calculate the Sum

Add the identified five digits:

Sum = 9 + 8 + 7 + 6 + 5

Sum = 35

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