If the sum of the roots of the equation \(\dfrac{1}{2x+p} + \dfrac{1}{2x+q} = \dfrac{1}{r}\) is zero, then what is \(r\) equal to?
\(\dfrac{p+q}{2}\)
Combining the fractions gives \(r(4x+p+q) = (2x+p)(2x+q) = 4x^2+2x(p+q)+pq\), i.e. \(4x^2+[2(p+q)-4r]x+[pq-r(p+q)]=0\). The sum of roots is zero, so \(2(p+q)-4r=0\), giving \(r=\dfrac{p+q}{2}\).
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For how many quadratic equations, the sum of roots is equal to the product of roots?
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