If cot α and cot β are the roots of the equation x 2+ bx + c = 0 with b ≠ 0, then the value of cot (α + β) is
We are given a quadratic equation \({x^2 + bx + c = 0}\) where \({b \neq 0}\). The roots of this equation are given as \({cot \alpha}\) and \({cot \beta}\).
For a quadratic equation of the form \({Ax^2 + Bx + C = 0}\), the sum of the roots is given by \({-B/A}\) and the product of the roots is given by \({C/A}\).
In our case, the equation is \({x^2 + bx + c = 0}\). Comparing this to \({Ax^2 + Bx + C = 0}\), we have \({A=1}\), \({B=b}\), and \({C=c}\). The roots are \({x_1 = \cot \alpha}\) and \({x_2 = \cot \beta}\).
Using the properties of the roots of a quadratic equation:
We need to find the value of \({\cot(\alpha + \beta)}\). The trigonometric identity for the cotangent of the sum of two angles is:
\({\cot(\alpha + \beta) = \frac{\cot \alpha \cot \beta - 1}{\cot \alpha + \cot \beta}}\)
Now, we can substitute the values we found for the sum and product of the roots into this formula.
We have \({\cot \alpha + \cot \beta = -b}\) and \({(\cot \alpha)(\cot \beta) = c}\).
Substituting these values into the formula for \({\cot(\alpha + \beta)}\):
\({\cot(\alpha + \beta) = \frac{(c) - 1}{(-b)}}\)
\({\cot(\alpha + \beta) = \frac{c - 1}{-b}}\)
To simplify and remove the negative sign in the denominator, we can multiply both the numerator and the denominator by \({-1}\):
\({\cot(\alpha + \beta) = \frac{(c - 1) \times (-1)}{(-b) \times (-1)}}\)
\({\cot(\alpha + \beta) = \frac{-c + 1}{b}}\)
This can also be written as:
\({\cot(\alpha + \beta) = \frac{1 - c}{b}}\)
| Property | Value from Equation |
|---|---|
| Sum of roots (\({cot \alpha + cot \beta}\)) | \({-b}\) |
| Product of roots (\({(cot \alpha)(cot \beta)}\)) | \({c}\) |
| Identity for \({cot(\alpha + \beta)}\) | \({\frac{cot \alpha cot \beta - 1}{cot \alpha + cot \beta}}\) |
| Calculated \({cot(\alpha + \beta)}\) | \({\frac{c - 1}{-b} = \frac{1 - c}{b}}\) |
Therefore, the value of \({\cot(\alpha + \beta)}\) is \({\frac{1 - c}{b}}\).
| Concept | Description | Formula/Relation |
|---|---|---|
| Roots of Quadratic Eq. | For \({Ax^2 + Bx + C = 0}\), roots \({x_1, x_2}\) | Sum of roots: \({x_1 + x_2 = -B/A}\) Product of roots: \({x_1 x_2 = C/A}\) |
| Cotangent Addition | Formula for \({cot}\) of sum of angles | \({\cot(A + B) = \frac{\cot A \cot B - 1}{\cot A + \cot B}}\) |
This problem is a good example of how concepts from algebra (properties of quadratic equations) and trigonometry (identities) can be combined. When roots of a quadratic equation are given in terms of trigonometric functions, you should always consider using the sum and product of roots relations and relevant trigonometric identities. The condition \({b \neq 0}\) is important because if \({b=0}\), the sum of roots \({cot \alpha + cot \beta = 0}\), which might lead to an undefined value in the denominator of the \({cot(\alpha + \beta)}\) formula if \({cot \alpha + cot \beta = 0}\) is the denominator, however, here the denominator is \(-b\), so \({b \neq 0}\) ensures the denominator \(-b\) is not zero.
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