If the ratio of two numbers is 6 : 4, and their HCF is 49, then their LCM is:
294
Ratio 6:4 simplifies to 3:2. Let the numbers be 3k and 2k. Since their HCF is 49, k=49.
Numbers: \(3\times49=147\) and \(2\times49=98\).
LCM: \(\dfrac{147\times98}{49} = 294\).
Hence, the LCM of the two numbers is 294.
Six bells begin to toll together and toll, respectively, at intervals of 3, 4, 6, 7, 8 and 12 seconds. After how many seconds, will they toll together again?
A and B are two prime numbers such that A > B and their LCM is 209. The value of A 2 - B is:
Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.
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Three numbers are in the proportion of 3 : 8 : 15 and their LCM is 8280. What is their HCF?