If the radius of a cone decreases by 20% when its height is increased by 50%, then what will be the percentage change in its volume?
4% decrease
Volume of cone = (1/3)πr²h, so the volume varies as r² × h.
New radius = 0.8r (20% decrease)
New height = 1.5h (50% increase)
New volume factor = (0.8)² × 1.5
= 0.64 × 1.5
= 0.96
Change = 0.96 - 1 = -0.04, i.e. 4% decrease
Hence, 4% decrease.
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