If the power of an engine is doubled while the time remains constant, the work done:
becomes double
Power is defined as the rate of doing work, so P = W / t, which rearranges to W = P × t.
If the time t is kept constant and the power P is doubled, then the work done becomes W' = (2P) × t = 2 × (P × t) = 2W.
So the new work done is exactly twice the original work done.
Hence, the correct answer is becomes double.
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