If the number 23P62971335 is divisible by the smallest odd composite number, then what is the value of P ?
4
The question asks us to find the value of the digit P in the number 23P62971335, given that this number is divisible by the smallest odd composite number. To solve this, we first need to identify what the smallest odd composite number is and then use the divisibility rule for that number.
Let's break down the term "smallest odd composite number":
Now let's list the first few natural numbers and categorize them:
| Number | Type (Odd/Even) | Type (Prime/Composite/Neither) | Notes |
|---|---|---|---|
| 1 | Odd | Neither | Only one factor (1) |
| 2 | Even | Prime | Factors: 1, 2 |
| 3 | Odd | Prime | Factors: 1, 3 |
| 4 | Even | Composite | Factors: 1, 2, 4 |
| 5 | Odd | Prime | Factors: 1, 5 |
| 6 | Even | Composite | Factors: 1, 2, 3, 6 |
| 7 | Odd | Prime | Factors: 1, 7 |
| 8 | Even | Composite | Factors: 1, 2, 4, 8 |
| 9 | Odd | Composite | Factors: 1, 3, 9 |
Looking at the list, the odd numbers are 1, 3, 5, 7, 9, ... Among these, we need the smallest one that is also composite. From our table, we see that 9 is the first number that is both odd and composite.
Therefore, the smallest odd composite number is 9.
The problem states the number 23P62971335 is divisible by the smallest odd composite number, which is 9. The divisibility rule for 9 states that a number is divisible by 9 if and only if the sum of its digits is divisible by 9.
The number is 23P62971335. The digits are 2, 3, P, 6, 2, 9, 7, 1, 3, 3, and 5.
Let's sum the known digits:
Sum of known digits \(= 2 + 3 + 6 + 2 + 9 + 7 + 1 + 3 + 3 + 5\)
Sum of known digits \(= 5 + 6 + 2 + 9 + 7 + 1 + 3 + 3 + 5\)
Sum of known digits \(= 11 + 2 + 9 + 7 + 1 + 3 + 3 + 5\)
Sum of known digits \(= 13 + 9 + 7 + 1 + 3 + 3 + 5\)
Sum of known digits \(= 22 + 7 + 1 + 3 + 3 + 5\)
Sum of known digits \(= 29 + 1 + 3 + 3 + 5\)
Sum of known digits \(= 30 + 3 + 3 + 5\)
Sum of known digits \(= 33 + 3 + 5\)
Sum of known digits \(= 36 + 5\)
Sum of known digits \(= 41\)
The total sum of the digits of the number 23P62971335 is \(41 + P\).
For the number to be divisible by 9, the sum of its digits (\(41 + P\)) must be a multiple of 9. The digit P can be any integer from 0 to 9 (since it's a single digit in the number).
Let's check the possible values for \(41 + P\) that are multiples of 9:
If \(41 + P = 36\), then \(P = 36 - 41 = -5\). This is not a valid digit.
If \(41 + P = 45\), then \(P = 45 - 41 = 4\). This is a valid digit (0-9).
If \(41 + P = 54\), then \(P = 54 - 41 = 13\). This is not a valid single digit.
Since P must be a single digit between 0 and 9, the only possible value for P is 4.
If P = 4, the number becomes 23462971335. The sum of digits is \(41 + 4 = 45\). Since 45 is divisible by 9 (\(45 \div 9 = 5\)), the number 23462971335 is indeed divisible by 9, which is the smallest odd composite number.
Thus, the value of P is 4.
| Concept | Definition/Rule | Relevance to Problem |
|---|---|---|
| Smallest Odd Composite Number | The smallest natural number that is both odd and has more than two factors. It is 9. | The divisor given in the problem. |
| Divisibility Rule for 9 | A number is divisible by 9 if the sum of its digits is divisible by 9. | Method used to find the missing digit P. |
| Sum of Digits | Adding all the digits of a number together. | Crucial calculation for applying the divisibility rule of 9. |
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