This problem involves finding the new average (mean) of a set of numbers when one specific number is taken out.
Initial Sum = Initial Mean \(\times\) Initial Count
Initial Sum = \(25 \times 15 = 375\)
New Sum = Initial Sum - Number Removed
New Sum = \(375 - 36.2 = 338.8\)
New Count = Initial Count - 1
New Count = \(15 - 1 = 14\)
New Mean = New Sum / New Count
New Mean = \(338.8 / 14 \approx 24.2\)
Therefore, the mean of the remaining 14 numbers is approximately 24.2.
| Marks obtained | No. of students |
| 25 | 5 |
| 30 | 6 |
| 35 | 3 |
| 40 | 1 |
| Age Band | Students |
|---|---|
| 0 - 10 | 4 |
| 10 - 20 | 5 |
| 20 - 30 | 15 |
| 30 - 40 | 4 |
The median of the observations 4, 14, 11, 8, 7, 8, 9, 12, 4, and 6 is:
The weights (in kg) of 9 members of a school cricket team are 50, 63, x, 62, 64, 48, 51, 55, 48. If the mean weight is 56 kg, then the value of x is:
A group of people consists of men, women, and children. 40% of them are men, 35% are women, and the rest are children, and their average weights are 70 kg, 60 kg, and 30 kg, respectively. The average weight of the group is:
If the mean of 22, 25, 27, 24, and x is 26, then the value of x is:
The average of 70 values is 40. If each value is multiplied by 20, what will be the changed average?
| Marks obtained | No. of students |
| 25 | 5 |
| 30 | 6 |
| 35 | 3 |
| 40 | 1 |
The average runs scored by a batsman in 23 matches is 40. In the next 10 matches, the batsman scored an average of 16 runs. Find his average runs scored (rounded off to two decimals) in all the 33 matches.