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Question

If the equations 4 x + 3 y + 5 = 0 and 6 x - k y - 7 = 0 have no solution, then the value of k is:

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is -4.5

Given:

T he equations 4 x + 3 y + 5 = 0  and  6 x  - k y - 7 = 0  have no solution.

Concept used:

If Ax + By + C = 0 and Px + Qy + R = 0 are two linear equations, then it has no solution if,

A/P = B/Q ≠ C/R

Calculation:

Since the equations  4 x + 3 y + 5 = 0  and  6 x  - k y - 7 = 0  have no solution,

According to the concept,

4/6 = 3/-k

⇒ k = -4.5

∴  The value of k is -4.5.

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