If the equation of a line is 2x+3y=6, what is the slope of the line?
-2/3
Write the equation in slope-intercept form \(y = mx + c\), where \(m\) is the slope.
\(2x + 3y = 6 \Rightarrow 3y = -2x + 6 \Rightarrow y = -\frac{2}{3}x + 2\)
Comparing with \(y = mx + c\), the slope is \(m = -\frac{2}{3}\).
Alternatively, for \(ax + by + c = 0\), slope \(= -\frac{a}{b} = -\frac{2}{3}\).
Hence, the slope of the line is \(-\frac{2}{3}\).
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In which ratio the point (-3, p) divides the line segment joining the points (-5, -4) and (-2, 3)?
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