Quadrant Location for Point (-16, 9)
The location of a point on a Cartesian plane is determined by the signs of its x and y coordinates. The plane is divided into four quadrants based on these signs.
Understanding Quadrant Signs
Here's a quick guide to the signs in each quadrant:
| Quadrant | X-coordinate | Y-coordinate |
|---|---|---|
| I | Positive (\(x > 0\)) | Positive (\(y > 0\)) |
| II | Negative (\(x < 0\)) | Positive (\(y > 0\)) |
| III | Negative (\(x < 0\)) | Negative (\(y < 0\)) |
| IV | Positive (\(x > 0\)) | Negative (\(y < 0\)) |
Analyzing the Point (-16, 9)
We need to determine the quadrant for the point (-16, 9).
- The x-coordinate is -16. Since -16 is less than 0, the x-coordinate is negative.
- The y-coordinate is 9. Since 9 is greater than 0, the y-coordinate is positive.
Conclusion
Based on the quadrant rules, a point with a negative x-coordinate and a positive y-coordinate lies in the II quadrant.
Similar Questions
- D is the midpoint of line segment AB. The co-ordinates of A and D are (2, 4) and (\(-1\), 3), respectively. The co-ordinates of B are:
- D is the midpoint of line segment AB. The co-ordinates of A and D are (2, 4) and (-1, 3), respectively. The co-ordinates of B are:
Important Questions from Co-ordinate Geometry
The graphs of the linear equations 4x - 2y = 10 and 4x + ky = 2 intersect at a point (a, 4). The value of k is equal to:
In which ratio the point (-3, p) divides the line segment joining the points (-5, -4) and (-2, 3)?
The area (in sq. units) of the triangle formed by the graphs of 8x + 3y = 24, 2x + 8 = y and the x-axis is:
In which quadrant both abscissa and ordinate are negative?
Find the slope of the line joining the points (3, -4) and (5, 2).
