The problem requires finding the value of $x$ given the coordinates of two points, $(x, 7)$ and $(1, 15)$, and the distance between them, which is 10 units. We can use the distance formula derived from the Pythagorean theorem.
The distance $d$ between two points $(x_1, y_1)$ and $(x_2, y_2)$ in a Cartesian coordinate system is given by the formula:
$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$
Here, $(x_1, y_1) = (x, 7)$, $(x_2, y_2) = (1, 15)$, and $d = 10$.
$10 = \sqrt{(1 - x)^2 + (15 - 7)^2}$
Calculate the difference in the y-coordinates and square it.
$10 = \sqrt{(1 - x)^2 + (8)^2}$
$10 = \sqrt{(1 - x)^2 + 64}$
$10^2 = (1 - x)^2 + 64$
$100 = (1 - x)^2 + 64$
Subtract 64 from both sides.
$(1 - x)^2 = 100 - 64$
$(1 - x)^2 = 36$
Remember that the square root of 36 can be positive or negative.
$1 - x = \pm\sqrt{36}$
$1 - x = 6 \quad \text{or} \quad 1 - x = -6$
$x = 1 - 6$
$x = -5$
$x = 1 - (-6)$
$x = 1 + 6$
$x = 7$
The possible values of $x$ are 7 and -5.
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