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Question

If the distance between two points $(x, 7)$ and $(1, 15)$ is 10 units, then the possible values of $x = ?$

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
7, -5

Using the Distance Formula to Find Coordinates

The problem requires finding the value of $x$ given the coordinates of two points, $(x, 7)$ and $(1, 15)$, and the distance between them, which is 10 units. We can use the distance formula derived from the Pythagorean theorem.

Distance Formula Explanation

The distance $d$ between two points $(x_1, y_1)$ and $(x_2, y_2)$ in a Cartesian coordinate system is given by the formula:

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Step-by-Step Calculation

  1. Substitute known values into the distance formula:

    Here, $(x_1, y_1) = (x, 7)$, $(x_2, y_2) = (1, 15)$, and $d = 10$.

    $10 = \sqrt{(1 - x)^2 + (15 - 7)^2}$

  2. Simplify the equation:

    Calculate the difference in the y-coordinates and square it.

    $10 = \sqrt{(1 - x)^2 + (8)^2}$

    $10 = \sqrt{(1 - x)^2 + 64}$

  3. Square both sides to eliminate the square root:

    $10^2 = (1 - x)^2 + 64$

    $100 = (1 - x)^2 + 64$

  4. Isolate the term containing $x$:

    Subtract 64 from both sides.

    $(1 - x)^2 = 100 - 64$

    $(1 - x)^2 = 36$

  5. Solve for $(1 - x)$ by taking the square root:

    Remember that the square root of 36 can be positive or negative.

    $1 - x = \pm\sqrt{36}$

    $1 - x = 6 \quad \text{or} \quad 1 - x = -6$

  6. Solve for $x$ in both cases:
    • Case 1: $1 - x = 6$

      $x = 1 - 6$

      $x = -5$

    • Case 2: $1 - x = -6$

      $x = 1 - (-6)$

      $x = 1 + 6$

      $x = 7$

Conclusion

The possible values of $x$ are 7 and -5.

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Similar Questions

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  2. The points A (1, 2), B (3, 4) and C (4, 1) are the vertices of a triangle which is:
  3. The area of the triangle formed by the line $2x - 4y - 7 = 0$ with the coordinate axis is:
  4. The distance between two points $(a \cos \alpha, 0)$ and $(0, a \sin \alpha)$ is_____.
  5. Find the area of a triangle formed by $(1, 0)$, $(-1, 0)$, $(0, 1)$.
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  7. The image of the point $(7, 8)$ when reflected along the x-axis is:
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Important Questions from Coordinate Geometry

  1. Find the co-ordinates of the centroid of a triangle whose vertices are A(1, 4), B(7, 8) and C(10, 12).

  2. If x² + y² - 16x + 38y + 425 = 0, then the value of x² + y² is:
  3. If x² + y² - 12x + 18y + 117 = 0, then the value of x² + y² is:
  4. A geological survey team has established three research stations forming a triangular monitoring zone. The stations are located at coordinates P(2,5), Q(8,1), and R(4,9) on a coordinate grid where each unit represents 1 kilometer. What is the area of the triangular monitoring zone?
  5. \(A(1, 2)\), \(B(a, -26)\), \(C(13, -14)\) and \(D(6, 14)\) are the vertices of a parallelogram, taken in order, find the value of \(a\).
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