If the difference between the perimeter of a square field A and its side is 48 cm. Side of square field B is 4 cm less than the side of square field A. Then, find the area of square field B.
144 cm2
We are given information about two square fields, let's call them Field A and Field B. We need to find the area of Field B.
Let the side length of square Field A be represented by the variable '$a$'.
The perimeter of a square is calculated by the formula: Perimeter = 4 × side.
So, the perimeter of Field A is $4a$ cm.
The problem states that the difference between the perimeter of Field A and its side is 48 cm.
We can write this as an equation:
Perimeter of A - Side of A = 48
Substituting the formula for the perimeter:
$$4a - a = 48$$
Now, we simplify the equation:
$$3a = 48$$
To find the side '$a$', we divide both sides by 3:
$$a = \frac{48}{3}$$
$$a = 16$$
Therefore, the side length of square Field A is 16 cm.
The problem states that the side of square Field B is 4 cm less than the side of square Field A.
Let the side length of square Field B be represented by the variable '$b$'.
Using the side length of Field A ($a = 16$ cm), we can find '$b$':
$$b = a - 4$$
$$b = 16 - 4$$
$$b = 12$$
So, the side length of square Field B is 12 cm.
The area of a square is calculated by the formula: Area = side × side or Area = side$^2$.
We need to find the area of square Field B, which has a side length '$b$' of 12 cm.
Area of Field B = $b^2$
Area of Field B = $12^2$
Area of Field B = $12 \times 12$
Area of Field B = 144
The area is measured in square centimeters (cm$^2$).
Thus, the area of square Field B is 144 cm$^2$.
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