Question
If the cubic equation \(a^3 - 4a^2 + 5a - 2 = 0\) has the roots x, y, z then find the value of x + y + z.
This question was previously asked in
SSC CGL 2025 Tier 2 Paper 1 Question Paper (19-Jan-2026)
The correct answer is
4
For a cubic equation \(a^3 + pa^2 + qa + r = 0\), the sum of roots is \(-p\) (Vieta's formula).
Here the equation is \(a^3 - 4a^2 + 5a - 2 = 0\), so \(p = -4\).
\(x + y + z = -(-4) = \mathbf{{4}}\)
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