If the axial ratio of an electromagnetic wave is zero dB. Then, the wave is:
circularly polarized
What the axial ratio is. As a polarised wave travels, the tip of its electric-field vector traces an ellipse in the transverse plane. The axial ratio (AR) is the ratio of the major axis of that ellipse to its minor axis, so by definition \(AR \ge 1\). In decibels:
\(AR_{dB} = 20\log_{10}(AR)\)
Step 1 — convert the given 0 dB back to a ratio.
\(0 = 20\log_{10}(AR) \Rightarrow \log_{10}(AR)=0 \Rightarrow AR = 1\)
Step 2 — interpret AR = 1. Major axis = minor axis, so the ellipse degenerates into a circle: the field vector keeps a constant magnitude and simply rotates at the wave frequency. That is circular polarisation, which physically requires two orthogonal components of equal amplitude and 90° phase difference.
Step 3 — check the other polarisation states against the same measure.
| Polarisation | Axial ratio | In dB |
|---|---|---|
| Circular | 1 | 0 dB |
| Elliptical | between 1 and ∞ | 0 to ∞ dB |
| Linear (horizontal or vertical) | ∞ (minor axis = 0) | ∞ dB |
So the given 0 dB rules out the elliptical case (which needs AR > 1) and both linear cases (horizontal and vertical polarisation have an infinite axial ratio, since the field simply oscillates along a line).
Why it matters in practice. Circular polarisation is used in satellite links and GPS because the received signal is insensitive to the relative orientation of transmitter and receiver antennas and is immune to Faraday rotation in the ionosphere. Real "circularly polarised" antennas are never perfect, so their specification quotes an axial ratio of a few dB (typically AR < 3 dB) over the operating band.
Hence, an axial ratio of 0 dB means the wave is circularly polarised.
A plane wave is propagating in a uniform medium with propagation constant \((0.6\pi + j\,0.4\pi)\) its wavelength is
Given below are two statements :
Statement I : Phase velocity of an electromagnetic wave in a bounded medium can be greater than the speed of light in an unbounded medium.
Statement II : Frequency of electromagnetic wave is affected by the permittivity of the medium.
In the light of the above statements, choose the correct answer from the options given below :
Assertion (A) : The ionosphere is that region of the earth’s atmosphere in which the constituent gases are ionised by radiations from outer space.
Reason (R) : Throughout the ionosphere, there are several layers in which ionization density either reaches maximum or remains almost constant. It depend on the intensity of sun. It also depends upon the atmospheric pressure.
Ultra High Frequency (UHF) spectrum is defined as :
Assertion (A) : Light is electromagnetic wave in nature, these may be x-rays, radio waves, microwaves etc.
Reason (R) : The amount of energy depends on the intensity of the light rays. The energy associated with each photon is proportional to the frequency.
Select your answer using the codes given below :
Frequency in UHF range propagated by means of
The free space wave number ‘k0’ is defined as
If the Polarization vector is given as N and the Direction of propagation is given as K then which one of the following relations is correct?
Ez ≠ 0 and Hz ≠ 0 represent which type of mode of propagation of microwaves?
A lossless transmission line has a characteristic impedance of Z0 and capacitance per unit length of C. The velocity of propagation of the travelling wave on the line is
The phenomenon of microwave signals following the curvature of earth is
The relationship between wavelength and frequency of an electromagnetic wave