If sinA = 3/5 and A is acute, then what is the value of cosA?
4/5
Given \(\sin A = \frac{3}{5}\), this corresponds to a right triangle with opposite side 3 and hypotenuse 5.
Using the Pythagorean theorem, the adjacent side is \(\sqrt{5^2 - 3^2} = \sqrt{25-9} = \sqrt{16} = 4\).
Since A is acute, \(\cos A = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{4}{5}\).
Hence, the answer is 4/5.
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