If sinA = $\frac{3}{5}$ and A is acute, then find the value of tanA × cot(90° - A).
$\frac{9}{16}$
Since \(\cot(90° - A) = \tan A\), the expression equals \(\tan A \times \tan A = \tan^2 A\). With sinA = 3/5, cosA = 4/5, so \(\tan A = 3/4\) and \(\tan^2 A = 9/16\).
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